is it a leap year in c++

[jimix]

here's what i have. using microsoft studio

#define _CRT_SECURE_NO_DEPRECATE
#include <stdio.h>
 
int main( void )
{
    int year, b, c, e;  
    b = 4;
    c = 100;
    e = 400;
 
    /* prompt the user for a year to check */
    printf("Enter a year:  ");
    scanf("%d", &year); 
    /* put your code below here */
 
    if ((year%b) != 0)                                                                                                       /*dividing the year by 4 and checking    remainder*/
 
printf("This year is not a leap year\n");
 
if ((year%b) == 0)    /*dividing the year by 100 and checking remainder*/
 
if ((year%e) != 0)    /*dividing the year by 400 and checking remainder*/
 
printf("This year is not a leap year\n");
 
if ((year%b) == 0)    /*dividing the year by 4 and checking remainder*/
 
if ((year%e) == 0)    /*dividing the year by 400 and checking remainder*/
 
printf("This year is a leap year\n");
 
}

it works well for years that are not leap years but any year like 1996, 2004 or 2008 says it's not a leap year and I don't understand why my last three lines don't solve this problem.

[Ganon11]

if ((year%b) == 0)    /*dividing the year by 100 and checking remainder*/
 
if ((year%e) != 0)    /*dividing the year by 400 and checking remainder*/
 
printf("This year is not a leap year\n");
 
if ((year%b) == 0)    /*dividing the year by 4 and checking remainder*/
 
if ((year%e) == 0)    /*dividing the year by 400 and checking remainder*/
 
printf("This year is a leap year\n");

These two sections have the same if statements, but different results. You also never use c.

In addition, if this is C++, why are you

1) using stdio.h?
2) using printf?
3) using scanf?

I think this is actually C.

[Arulmurugan]

here's what i have. using microsoft studio

#define _CRT_SECURE_NO_DEPRECATE
#include <stdio.h>
 
int main( void )
{
    int year, b, c, e;  
    b = 4;
    c = 100;
    e = 400;
 
    /* prompt the user for a year to check */
    printf("Enter a year:  ");
    scanf("%d", &year); 
    /* put your code below here */
 
    if ((year%b) != 0)                                                                                                       /*dividing the year by 4 and checking    remainder*/
 
printf("This year is not a leap year\n");
 
if ((year%b) == 0)    /*dividing the year by 100 and checking remainder*/
 
if ((year%e) != 0)    /*dividing the year by 400 and checking remainder*/
 
printf("This year is not a leap year\n");
 
if ((year%b) == 0)    /*dividing the year by 4 and checking remainder*/
 
if ((year%e) == 0)    /*dividing the year by 400 and checking remainder*/
 
printf("This year is a leap year\n");
 
}

it works well for years that are not leap years but any year like 1996, 2004 or 2008 says it's not a leap year and I don't understand why my last three lines don't solve this problem.

where do you use "c=100", i could not find it.

algorithm is
if( ( year % 400 == 0) || (( year % 4 == 0 ) && ( year %100 != 0 )) ){
leap year
else
not a leap year.

Regards
Arul

[weaknessforcats]

Actually, I belive the algorithm is:

A year will be a leap year if it is divisible by 4 but not by 100. If a year is divisible by 4 and by 100, it is not a leap year unless it is also divisible by 400.

Thus years such as 1996, 1992, 1988 and so on are leap years because they are divisible by 4 but not by 100. For century years, the 400 rule is important. Thus, century years 1900, 1800 and 1700 while all still divisible by 4 are also exactly divisible by 100. As they are not further divisible by 400, they are not leap years.

[jimix]

O.k. Thanks for your help. I understand the algorithm and tried an "else" statement.(it seems simpler this way) I get one error here and don't know what I am missing. This is c not c++ and my original post had some integer mistakes.

#define _CRT_SECURE_NO_DEPRECATE
#include <stdio.h>
 
int main( void )
{
    int year, a, b, e;  
    a = 4;
    b = 100;
    e = 400;
 
    /* prompt the user for a year to check */
    printf("Enter a year:  ");
    scanf("%d", &year); 
 
    if (year%e == 0) 
 
    if (year%b != 0) && (year%a == 0)
 
        printf("This is a leap year\n")
    else
        printf("This is not a leap year\n")
 
    }

[jimix]

nevermind I figured it out. (with your help). thanks.