Void pointer

[howa]

int i = 10;
void *j = &i;
How to print out the integer "10" ?

Thanks.

[Ian Collins]

howa wrote:

int i = 10;
void *j = &i;
How to print out the integer "10" ?

#include <iostream>

int main() { std::cout << 10 << std::endl; }

Or where you asking something else?

--
Ian Collins.

[Ian Collins]

Alf P. Steinbach wrote:

* howa:

>int i = 10;
void *j = &i;
How to print out the integer "10" ?

#include <iostream>
int main
{
std::cout << "10" << std::endl;
}

Echo?

--
Ian Collins.

[howa]

On 1$B7n(B24$BF|(B, $B2<8a(B4$B;~(B08$BJ,(B, "Alf P. Steinbach" <[e-mail]:

* howa:

int i = 10;
void *j = &i;

How to print out the integer "10" ?

Technically the answer is to cast the pointer and dereference it,
*static_cast<int*>(j).

However, as a novice you should not use raw pointers at all, much less
void* pointers: what's the problem you're trying to use void* to solve?

How does the following one compare with static_cast?

e.g. cout<< *(int*)j;
Howard

[Ian Collins]

howa wrote:

On 1$B7n(B24$BF|(B, $B2<8a(B4$B;~(B08$BJ,(B, "Alf P. Steinbach" <[e-mail]:

>* howa:

>>int i = 10;
void *j = &i;
How to print out the integer "10" ?

Technically the answer is to cast the pointer and dereference it,
*static_cast<int*>(j).

However, as a novice you should not use raw pointers at all, much less
void* pointers: what's the problem you're trying to use void* to solve?

How does the following one compare with static_cast?

e.g. cout<< *(int*)j;

It's harder to search for in code and more likely to hide errors (the
compiler will reject inappropriate use of static_cast).

--
Ian Collins.

[howa]

On 1$B7n(B24$BF|(B, $B2<8a(B5$B;~(B44$BJ,(B, Ian Collins <[e-mail]:

howa wrote:

On 1$B7n(B24$BF|(B, $B2<8a(B4$B;~(B08$BJ,(B, "Alf P. Steinbach" <[e-mail]:

* howa:

>int i = 10;
void *j = &i;
How to print out the integer "10" ?
Technically the answer is to cast the pointer and dereference it,
*static_cast<int*>(j).

However, as a novice you should not use raw pointers at all, much less
void* pointers: what's the problem you're trying to use void* to solve?

How does the following one compare with static_cast?

e.g. cout<< *(int*)j;

It's harder to search for in code and more likely to hide errors (the
compiler will reject inappropriate use of static_cast).

--
Ian Collins.- $Bp,i6Ho0zMQJ8;z(B -

- $Bp}<(Ho0zMQJ8;z(B -

Thanks.