Storing address of pointer (cross platform)

[howa]

In 32 bit pc, I can write

e.g.

char* p1 = "apple";
cout<<(int)p1;
In 64 bit pc, I need to use

char* p1 = "apple";
cout<<(__int64)p1;
What are the cross platform way to so?

Thanks.

[=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?=]

On 2008-01-19 13:47, howa wrote:

In 32 bit pc, I can write

e.g.

char* p1 = "apple";
cout<<(int)p1;
In 64 bit pc, I need to use

char* p1 = "apple";
cout<<(__int64)p1;
What are the cross platform way to so?

If your platforms have C compilers providing <stdint.hyou can check if
they define the typedef intptr_r or uintptr_t, they should be large
enough for a void pointer. If you do not have those typedefs you need to
provide them (or similar) on your own.

--
Erik Wikström

[howa]

On 1月19日, 下�9時12分, Erik Wikström <[e-mail]:

On 2008-01-19 13:47, howa wrote:

In 32 bit pc, I can write

e.g.

char* p1 = "apple";
cout<<(int)p1;

In 64 bit pc, I need to use

char* p1 = "apple";
cout<<(__int64)p1;

What are the cross platform way to so?

If your platforms have C compilers providing <stdint.hyou can check if
they define the typedef intptr_r or uintptr_t, they should be large
enough for a void pointer. If you do not have those typedefs you need to
provide them (or similar) on your own.

--
Erik Wikström

Thanks.

[=?iso-8859-1?q?Tom=E1s_=D3_h=C9ilidhe?=]

howa:

In 32 bit pc, I can write

e.g.

char* p1 = "apple";
cout<<(int)p1;
In 64 bit pc, I need to use

char* p1 = "apple";
cout<<(__int64)p1;
What are the cross platform way to so?

I'm not sure if cout can print a pointer, but printf certainly can:

int i;

printf("%p",(void*)&i);

--
Tomás Ó hÉilidhe

[Rolf Magnus]

howa wrote:

In 32 bit pc, I can write

e.g.

char* p1 = "apple";
cout<<(int)p1;
In 64 bit pc, I need to use

char* p1 = "apple";
cout<<(__int64)p1;
What are the cross platform way to so?

cout << static_cast<void*>(p1);

[James Kanze]

On Jan 19, 1:47 pm, howa <[e-mail]:

In 32 bit pc, I can write

e.g.

char* p1 = "apple";
cout<<(int)p1;

In 64 bit pc, I need to use

char* p1 = "apple";
cout<<(__int64)p1;

(A more portable 64 bit type would be long long.)

What are the cross platform way to so?

cout << static_cast< void* >( p1 ) ;

It's the only way guaranteed to work everywhere.

It doesn't allow you to control the output format in any way,
however. If you need to control the output format, something
like:
cout << static_cast< uintptr_t >( p1 ) ;
will usually work (but uintptr_t is not guaranteed to be present
on a machine where pointers are larger than 64 bits).

If you have to work with an older compiler, which doesn't
support the new integer types, then casting to size_t is often
OK (although I've used platforms where it wouldn't work).

--
James Kanze (GABI Software) email:ja*********@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientierter Datenverarbeitung
9 place Sémard, 78210 St.-Cyr-l'École, France, [phone]