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Reference are always lvalue?

Hello everyone,
Is the conclusion correct? Both const reference and non-const
reference are lvalue?

I think it is true and I can not find a sample which does not follow
it.
thanks in advance,
George

Dec 21 '07 #1

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George2 wrote:

Is the conclusion correct? Both const reference and non-const
reference are lvalue?

I think it is true and I can not find a sample which does not follow
it.

If an expression has the type 'reference to T', it's an lvalue. See
[expr]/6. I presume by "const reference" and "non-const reference"
you actually mean "reference to const" and "reference to non-const".

V
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Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

Dec 21 '07 #2

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