Ambiguous call to overloaded function

[Joseph Turian]

I have a templated class with the following methods:
Vocab(const T& t);
Vocab(unsigned uid);

However, when T = unsigned, and I call Vocab(unsigned(0)) then the
compiler rightly complains about an ambiguous call to the overloaded
function.
How can I specify which method I want called in this case?

Thanks,
Joseph

[Salt_Peter]

On Dec 19, 11:45 pm, Joseph Turian <[e-mail]:

I have a templated class with the following methods:
Vocab(const T& t);
Vocab(unsigned uid);

However, when T = unsigned, and I call Vocab(unsigned(0)) then the
compiler rightly complains about an ambiguous call to the overloaded
function.
How can I specify which method I want called in this case?

Thanks,
Joseph

One way is by using a dummy variable to change the member function's
signature
ie:
template < typename T >
class Test
{
...
public:
void Vocab(const T& t);
void Vocab(unsigned u, int dummy);
};

The better way might be to reduce the confusion:

template < typename T >
class Test
{
...
public:
void setT(const T& t);
void setuid(unsigned u);
};

[Ioannis Gyftos]

The better way might be to reduce the confusion:

[...]

I believe that he wants to do it in a constructor.

However, when T = unsigned, and I call Vocab(unsigned(0)) then the
compiler rightly complains about an ambiguous call to the overloaded
function.
How can I specify which method I want called in this case?

Hmm, given that one is const and the other is not, does the explicit
keyword work?

[Ian Collins]

Joseph Turian wrote:

I have a templated class with the following methods:
Vocab(const T& t);
Vocab(unsigned uid);

However, when T = unsigned, and I call Vocab(unsigned(0)) then the
compiler rightly complains about an ambiguous call to the overloaded
function.
How can I specify which method I want called in this case?

Call it indirectly through a function template.

The most specialised function matches first, so a regular function
matches before a function template.

--
Ian Collins.

[tragomaskhalos]

On Dec 20, 8:07 am, Ian Collins <[e-mail]:

Joseph Turian wrote:

I have a templated class with the following methods:
Vocab(const T& t);
Vocab(unsigned uid);

However, when T = unsigned, and I call Vocab(unsigned(0)) then the
compiler rightly complains about an ambiguous call to the overloaded
function.
How can I specify which method I want called in this case?

Call it indirectly through a function template.

The most specialised function matches first, so a regular function
matches before a function template.

--
Ian Collins.

Clever, but pity the poor maintenance programmer !
Giving the functions different names is less elegant but better for
posterity ...