return type of conversion opeator

[George2]

Hello everyone,


In a class T, if there is a conversion opeator G, we always define it like this,

operator G()

without return type. So the implicit return type is G or G&? I can not find it in the C++ programming language book. :-)


thanks in advance,
George

[sicarie]

Did you try coding an example of it yourself? Try to create a class, and an operator in the class, and see what happens.

[weaknessforcats]

If you return G, then you can use your object as a G.
If you return G&, the you can use your object as a G&.

[George2]

Thanks weaknessforcats,


I assume they both should be correct code, right?

If you return G, then you can use your object as a G.
If you return G&, the you can use your object as a G&.

regards,
George

[George2]

Thanks sicarie,

Did you try coding an example of it yourself? Try to create a class, and an operator in the class, and see what happens.

I have tried it and both work. I am not sure whether it is good code (even if function works).


regards,
George