C, C++ and Java Expression same but results different

[anwar7517525]

In Turbo C 3.0
#include<conio.h>
#include<stdio.h>
void main(void)
{

int x=-250;

x = --x + --x + --x;

printf("%d",x);

getch();

}//it gives: -259

In Visual C++ 6.0
#include<iostream>
using namespace std;
void main(void)
{

int x=-250;

x = --x + --x + --x;

cout <<x;

}//it gives: -257

In Java
class Test
{
public static void main(String abc[])
{

int x=-250;

x = --x + --x + --x;

System.out.print(x);

}//it gives: -256

[sicarie]

Cool.

Next time you post, please be sure to follow the Posting Guidelines which ask that you do things like use code tags, etc...

[mschenkelberg]

In Turbo C 3.0
#include<conio.h>
#include<stdio.h>
void main(void)
{

int x=-250;

x = --x + --x + --x;

printf("%d",x);

getch();

}//it gives: -259

In Visual C++ 6.0
#include<iostream>
using namespace std;
void main(void)
{

int x=-250;

x = --x + --x + --x;

cout <<x;

}//it gives: -257

In Java
class Test
{
public static void main(String abc[])
{

int x=-250;

x = --x + --x + --x;

System.out.print(x);

}//it gives: -256

I think you mean they give 75* not 25* but anyway

It is based on the order of operations specific to compilers

If Turbo does give 759 and not 259 then it will always perform the decrement operation first on before doing anything resulting in -253 + -253 + -253

In Visual C++ they do the same thing but only look at 2 items at a time so it will take the last items, do the decrements then add them together so you have -250 decremented, then -251 decremented resulting in -252 + -252 giving -504. -504 is then added to x decremented which is -504 + -253 giving -757

Java decrements then adds so x is decremented to -251 and added to that decremented -252 which is added to that decremented -253 resulting in -756

Parenthesis would help resolve how you want it evaluated

[weaknessforcats]

x = --x + --x + --x;

Your results are indeterminate.

Variables can be modified only once in a statement. More than that and your results are unpredictable.