Question about arrays

[ledzepfan32]

On a recent quiz i got a question wrong but am unsure of it..
The problem passed an array to a function by value, without a reference (&), incremented the values by 1, then returned the array. If an array does not have a reference, does it still pass by reference?

void foo(int Arr[], int s)
{
for(int I=0; I<s; I++)
Arr[i]=Arr[i]+1
}

int a[5]={0,1,2,3,4};
foo(a, 5);
cout<<a[4]<<endl;


I answered 4, but apparently the array was incremented and returned as 5 even tho there is no reference..

[oler1s]

Arrays can be tricky when it comes to passing them in for functions. Which leads to a lot of misconceptions by even experienced programmers. I would suggest you read the C-FAQ on arrays and pointers. 6.2 to 6.4b should be useful reading, and any links from those points.

It is confusing initially. Let us know if you don't understand what you read (and what part of it you didn't understand).

EDIT: And to answer your question. Arrays are never passed by value, So when you pass in an array, yes, it is modifiable like you had passed it by reference.