the format for conversion of double in the function printf is
"%f" or "%lf" or both?
for example
printf("%f", (double)0.0);
printf("%lf", (double)0.0);
are both ok?
Good morning
Thank you
6  16695 
it seems like that in c there is no need to print a double varible
with %lf format
%f is ok
but for long interger , u should use %ld
RoS wrote:
the format for conversion of double in the function printf is
"%f" or "%lf" or both?
for example
printf("%f", (double)0.0);
printf("%lf", (double)0.0);
are both ok?
Good morning
Thank you
RoS wrote:
the format for conversion of double in the function printf is
"%f" or "%lf" or both?
for example
printf("%f", (double)0.0);
printf("%lf", (double)0.0);
are both ok?
Yes they are equivalent, the l modifier has no effect for the f specifier.
--
Ian Collins.
Ian Collins wrote:
>
RoS wrote:
the format for conversion of double in the function printf is
"%f" or "%lf" or both?
for example
printf("%f", (double)0.0);
printf("%lf", (double)0.0);
are both ok?
Yes they are equivalent,
the l modifier has no effect for the f specifier.
That's the case for C99.
For C89,
a function call to printf is undefined
if "%lf" is the first argument.
--
pete
On Dec 3, 3:49 pm, pete <pfil...@mindspring.comwrote:
Ian Collins wrote:
RoS wrote:
the format for conversion of double in the function printf is
"%f" or "%lf" or both?
for example
printf("%f", (double)0.0);
printf("%lf", (double)0.0);
are both ok?
Yes they are equivalent,
the l modifier has no effect for the f specifier.
That's the case for C99.
For C89,
a function call to printf is undefined
if "%lf" is the first argument.
The first? "%d %lf" is not undefined? vi******@gmail.com writes:
On Dec 3, 3:49 pm, pete <pfil...@mindspring.comwrote:
>Ian Collins wrote:
RoS wrote:
the format for conversion of double in the function printf is
"%f" or "%lf" or both?
for example
printf("%f", (double)0.0);
printf("%lf", (double)0.0);
are both ok?
Yes they are equivalent,
the l modifier has no effect for the f specifier.
That's the case for C99.
For C89,
a function call to printf is undefined
if "%lf" is the first argument.
The first? "%d %lf" is not undefined?
Yes, "%d %lf" is undefined for C89/C90's printf. He said "if", not
"if and only if".
(Incidentally, given printf("%d %lf", x, y), the first *argument*
isn't %d; it's the string "%d %ld".)
--
Keith Thompson (The_Other_Keith) <ks***@mib.org>
Looking for software development work in the San Diego area.
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
In article <47***********@mindspring.com>,
pete <pf*****@mindspring.comwrote:
>Ian Collins wrote:
>>
RoS wrote:
the format for conversion of double in the function printf is
"%f" or "%lf" or both?
>Yes they are equivalent,
the l modifier has no effect for the f specifier.
>That's the case for C99.
For C89,
a function call to printf is undefined
if "%lf" is the first argument.
And just to confuse matters, in C89, "%Lf" *is* defined and
indicates that the corresponding argument is long double .
--
"There are some ideas so wrong that only a very intelligent person
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