printing variable type at run time

[manontheedge]

I'm having a problem remembering how to get the type of a variable at run time. For example, lets say I have a char* i, and at some point during execution, it is converted to an int. What I want is a function so I can output i's type during execution ( so it will print to the console and I'll see it ).

I did this a few weeks ago, but I can not remember what the function is that does this. I searched around, and found typeid, but either I'm using it wrong, or that wasn't it. If anyone can tell me the function I'm looking for I would really appreciate it.

[MarshMallow]

It looks like today everyone is interested in reflection.
As you just wrote,typeid should work;
correct syntax is: typeid(variable).name();
please send us your code so we can examine together the possible errors.

[MarshMallow]

#include <iostream>
#include <typeinfo>
 
using namespace std;
int main ()
  {
     int a = 5 ;
     double b = 6.999998;
cout << typeid(a).name() << endl;
cout << typeid(b).name() << endl; 
   return 0;
  }
 

it prints:
i
d

[manontheedge]

I feel like an idiot now. I was using the variable "i" and it looked like the variable name was being printed. I guess it's early. Anyway, thank you for the help. I was posting my code when I saw your output, and realised my mistake.

[weaknessforcats]

I assume you are using typeid for debugging since using it is poor porogramming practice. Assuming that you are debugiing, you should be using your debugger rather than relying on console displays.

typeid requires RTTI and that reuires the compiler to keep a database for every variable in the program on the off-chance you will typeid the thing. This is very expensive in terms of machine resources.