Function argument error?

[mosullivan]

I don't know where the problem with my program is. I keep getting an error that says the function doesn't take 1 argument. I have two arguments listed for the function everytime I mention it. The error is said to be in line 46. Any help would be great.

#include <stdio.h>
 
int total(int hi, int count);
 
int main (int)
{
    int n;        /*Input by the user*/
    int m;        /*Input by the user*/
    int lo;        /*Assigned the lower number*/
    int hi;        /*Assigned the higher number*/
    int count;
 
    /*Prompt the user to input 2 numbers*/
 
    printf("This program will add the range of numbers entered.");
 
    printf("\n\nEnter the low number and the high number.\n\n");
 
    /*Accept the user input*/
 
    scanf("%d%d", &n, &m);
 
    /*Determines the hi and lo*/
 
    lo = (n < m) ? n : m;        /*Assigns the lower number to lo*/
    hi = (n > m) ? n : m;        /*Assigns the higher number to hi*/
 
    count = (hi - lo) + 1;        /*Counts the total number of numbers in range*/
 
    /*Call function*/
 
    total(hi, count);
 
    printf("\nThe sum of the range of numbers %d and %d is %d.\n\n", lo, hi, total(hi, count));
 
 
}
 
#include <stdio.h>
int total(int hi, int count)
 
{ 
    if (count == 1)
        return (hi + 1);
    else
        return (hi + total(hi - (count - 1)));
 
}
 

[scruggsy]

int total(int hi, int count);
 
...
 
return (hi + total(hi - (count - 1)));
 
 

You're calling total(), which takes 2 arguments, with only 1 argument.
hi - (count - 1) is only one argument.

[mosullivan]

Ok, I understand that. I've changed it so that count is a function and now I'm getting an error that says 'lo' is an undeclared identifier. Both hi and lo are identified in the main - is there something I'm missing?

#include <stdio.h>
 
int total(int hi);
int count(int hi, int lo);
 
int main (int)
{
    int n;        /*Input by the user*/
    int m;        /*Input by the user*/
    int lo;        /*Assigned the lower number*/
    int hi;        /*Assigned the higher number*/
 
 
    /*Prompt the user to input 2 numbers*/
 
    printf("This program will add the range of numbers entered.");
 
    printf("\n\nEnter the low number and the high number.\n\n");
 
    /*Accept the user input*/
 
    scanf("%d%d", &n, &m);
 
    /*Determines the hi and lo*/
 
    lo = (n < m) ? n : m;        /*Assigns the lower number to lo*/
    hi = (n > m) ? n : m;        /*Assigns the higher number to hi*/
 
    count(hi, lo);
 
    /*Call function*/
 
    total(hi);
 
    printf("\nThe sum of the range of numbers %d and %d is %d.\n\n", lo, hi, total(hi));
 
 
}
#include <stdio.h>
 
int count(int hi, int lo);
int total(int hi)
 
{ 
    if ((count(hi, lo)) = 1)
        return (hi + 1);
    else
        return (hi + total(hi - ((count(hi, lo) - 1))));
 
}
#include <stdio.h>
 
int count(int hi, int lo)
{
    int cnt = 0;
 
    cnt = (hi - lo) + 1;        /*Counts the total number of numbers in range*/
 
    return 1;
}
 
 

[Ganon11]

What is that mess at the end? You are #include <stdio.h> three times, and you declare count twice before defining. There's no need for the extra definitions and #includes after the top of the program. Anyway, your problem is in total - you use count(hi, lo), but you never got lo from main, only a variable named hi as an argument.

[mosullivan]

What is that mess at the end? You are #include <stdio.h> three times, and you declare count twice before defining. There's no need for the extra definitions and #includes after the top of the program. Anyway, your problem is in total - you use count(hi, lo), but you never got lo from main, only a variable named hi as an argument.

The mess are the two functions. I guess I should have titled them so I didn't cause any confusion. I'll look at total again. Thanks

[mosullivan]

The mess are the two functions. I guess I should have titled them so I didn't cause any confusion. I'll look at total again. Thanks

I started over and have completed the assignment. Thanks for all your help.