int *x=new int[38200]; is this correct??

[prads]

Hello,
I have done the following initialization in my C++ code:
int *x=new int[38200];
However a doubt arouse to me now..... int can take values only from 2^15 to (2^15)-1..........So do i have to change it to something like
long int *x=new long int[38200] or is it ok coz its allocating dynamic memory?? If I have to change, then what should it be i.e is my new initialization correct?
Thanks,
prads

[oler1s]

Whoa, stop. Let's get something straight. The 38200 is an argument to new. For example, you quite often have character pointers. Does that mean you can't have char *str = new char[1024]? Obviously not. The 1024 has nothing to do with char. It just specifies how many of the type to allocate.

If you want 38200 ints, say so. By the way, a size won't be negative, so even if the size were limited to an integer, it would be an unsigned int, so that's 2^16-1. But the parameter for new is size_t . size_t is probably much bigger than a uint on your system though.