convert Void * to an int using GCC 4.1.1

[nano2]

Hi ,

I have the following where i want to take a void * and convert it to an int
void *contending(void *arg)
{
int delta = (void *) arg;
}

error: invalid conversion from void* to int

Any ideas how i can achieve this using GCC 4.1.1

Any help much appreciated !

[sicarie]

As far as I know, you can't have a pointer to a void. Void is a keyword to tell the compiler not to expect anything - as in the return type of the function you have. Where did you get *arg? Does it have a type in your main()?

[Cucumber]

How about using this:

   int delta = (int) arg;
 

[nano2]

How about using this:

   int delta = (int) arg;
 

Thanks all ....
Goit it sorted using this -- some comoilers threat void differently

int delta= (long int)arg;

[sicarie]

Thanks all ....
Goit it sorted using this -- some comoilers threat void differently

int delta= (long int)arg;

yeah, nano2, I just wanted to say thanks, I'd never seen that, so I spent the last few days researching other uses of void like that. You learn something new every day...

[Jose Diaz]

There so many ways of doing it check this out:

void *contending(void *arg)
{
int *delta = (int *)arg;
printf("%d\n",delta); //printing out to sreen
}
 

delta is a pointer to integer then we cast arg which is a void * unto an integer of int.

When passing a paramater when calling function is like this: contending((int*)3100); we cast it like that.

I Hope i helped !!! =)