std::valarray as value in std::map

[Chris Forone]

Hello group,

g++ (3.4.2, mingw):

float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

mp["name"] = std::valarray(init, 3);
mp["name"].size(); // should be 3, but IS 0!

Do i ignored something? Does map not do a copy of value?

HAND, Chris

[Chris Forone]

Chris Forone schrieb:

Hello group,

g++ (3.4.2, mingw):

float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

mp["name"] = std::valarray(init, 3);
mp["name"].size(); // should be 3, but IS 0!

Do i ignored something? Does map not do a copy of value?

HAND, Chris

compilable:

#include <iostream>
#include <map>
#include <valarray>

int main()
{
float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

mp["name"] = std::valarray<float>(init, 3);

std::cout << mp["name"].size() << std::endl;
}

g++ (4.1.2, ubuntu) has the same behavior...

Chris

[Chris Forone]

Chris Forone schrieb:

Chris Forone schrieb:

>Hello group,

g++ (3.4.2, mingw):

float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

mp["name"] = std::valarray(init, 3);
mp["name"].size(); // should be 3, but IS 0!

Do i ignored something? Does map not do a copy of value?

HAND, Chris

compilable:

#include <iostream>
#include <map>
#include <valarray>

int main()
{
float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

mp["name"] = std::valarray<float>(init, 3);

std::cout << mp["name"].size() << std::endl;
}

g++ (4.1.2, ubuntu) has the same behavior...

Chris

SOLVED!

..insert does the trick... operator[] only does std-ctor...

HAND, Chris

[Pete Becker]

On 2007-11-03 10:20:01 -0400, Chris Forone <4o**@gmx.atsaid:

Chris Forone schrieb:

>Chris Forone schrieb:

>>Hello group,

g++ (3.4.2, mingw):

float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

mp["name"] = std::valarray(init, 3);
mp["name"].size(); // should be 3, but IS 0!

Do i ignored something? Does map not do a copy of value?

HAND, Chris

compilable:

#include <iostream>
#include <map>
#include <valarray>

int main()
{
float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;
mp["name"] = std::valarray<float>(init, 3);
std::cout << mp["name"].size() << std::endl;
}

g++ (4.1.2, ubuntu) has the same behavior...

Chris

SOLVED!

.insert does the trick... operator[] only does std-ctor...

No, it doesn't. It just happens to look like it works. The problem has
nothing to do with valarray: you'll see the same behavior with any type
for the value. The problem is in the index, not the value. Quoted
strings are not guaranteed to be unique, so mp["name"] may be a
different map element than some other mp["name"].

--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

[James Kanze]

On Nov 5, 2:22 pm, Pete Becker <[e-mail]:

On 2007-11-03 10:20:01 -0400, Chris Forone <[e-mail]:

Chris Forone schrieb:

Chris Forone schrieb:
Hello group,

>g++ (3.4.2, mingw):

>float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;

>mp["name"] = std::valarray(init, 3);
mp["name"].size(); // should be 3, but IS 0!

>Do i ignored something? Does map not do a copy of value?

>HAND, Chris

compilable:

#include <iostream>
#include <map>
#include <valarray>

int main()
{
float init[] = {1.f, 2.f, 3.f};
std::map<std::string, std::valarray<float mp;
mp["name"] = std::valarray<float>(init, 3);
std::cout << mp["name"].size() << std::endl;
}

g++ (4.1.2, ubuntu) has the same behavior...

SOLVED!

.insert does the trick... operator[] only does std-ctor...

No, it doesn't. It just happens to look like it works. The
problem has nothing to do with valarray: you'll see the same
behavior with any type for the value. The problem is in the
index, not the value. Quoted strings are not guaranteed to be
unique, so mp["name"] may be a different map element than some
other mp["name"].

But his map uses std::string as a key, not char const*, so the
string literal will be converted.

I'm not familiar enough with valarray to really comment, but his
initial use of std::map seems correct: the call to mp["name"]
does insert a valarray constructed withe the default
constructor, before returning a reference to the new object; the
assignment operator then does whatever the assignment operator
for valarray does.

--
James Kanze (GABI Software) email:ja*********@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientierter Datenverarbeitung
9 place Sémard, 78210 St.-Cyr-l'École, France, [phone]

[Pete Becker]

On 2007-11-05 12:13:44 -0500, James Kanze <ja*********@gmail.comsaid:

On Nov 5, 2:22 pm, Pete Becker <[e-mail]:

>No, it doesn't. It just happens to look like it works. The
problem has nothing to do with valarray: you'll see the same
behavior with any type for the value. The problem is in the
index, not the value. Quoted strings are not guaranteed to be
unique, so mp["name"] may be a different map element than some
other mp["name"].

But his map uses std::string as a key, not char const*, so the
string literal will be converted.

Whoops, sorry about confusing the issue.

--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)