RTTI in C++

[ashitpro]

consider Following pseudocode...

display(x)
{
if x is of type int
print "integer found"
if x is of type float
print "Float found"
}
main()
{
//few declarations.
display(x);

}

We can achieve this is Python or Ruby easily.
I have problem in C++.
Although, We can use "typeid(variable_name).name()" to get the class name.,
We get trapped while declaring the above "display" function as.

display(int or float or somthing_else);

because at the time of declaration we never know, what kind of variable will be.

So, In short How can I achieve this in C++?

Don't say that It can't be done in C++.
Ofcourse this may not be a challenge for some people.

[r035198x]

consider Following pseudocode...

display(x)
{
if x is of type int
print "integer found"
if x is of type float
print "Float found"
}
main()
{
//few declarations.
display(x);

}

We can achieve this is Python or Ruby easily.
I have problem in C++.
Although, We can use "typeid(variable_name).name()" to get the class name.,
We get trapped while declaring the above "display" function as.

display(int or float or somthing_else);

because at the time of declaration we never know, what kind of variable will be.

So, In short How can I achieve this in C++?

Don't say that It can't be done in C++.
Ofcourse this may not be a challenge for some people.

Moved to C++ forum

[Banfa]

use a template function and specialise it for the basic types.

The reason this is not as easy as it is in those scripting languages is that C++ has strong typing, that is variables have to be given a type when they are declared so there is never any question as to what there type is so it is rarely necessary to have code that makes this determination.