Manipulate char* to increment next offset value.

[avinash6174]

 
#include <iostream>
using namespace std;
typedef char TUCHAR8;
 
typedef   signed char  TINT8;    /* Must force decl to be signed   */
typedef unsigned char  TUINT8;   /* Must force decl to be unsigned */
 
typedef          short TINT16;   /* Decl will be signed as per std */
typedef unsigned short TUINT16;  /* Must force decl to be unsigned */
 
typedef          int   TINT32;   /* Decl will be signed as per std */
typedef unsigned int   TUINT32;  /* Must force decl to be unsigned */
 
 
void putBits(TUCHAR8 *des ,const TUINT32 offset, const TUINT32 length,const TINT32 value)
{
 
    TUCHAR8 *pTempData;
    for(loop = 0 ; loop < offset; loop++)
    {
        pTempData++;
    }
 
    pTempData  = des[offset];
//  pTempData[offset];
    TUINT16 loop;
 
cout<<"\n The value of temp is "<<pTempData[offset]<<endl;
}
 
int main()
{
    TUCHAR8 *des;
    des = new TUCHAR8 [8];
    des = "avinash";
    TINT32 value1 = 0xaa , value2 = 0xff;
    putBits(des , (TUINT32)2 ,0x8 , value1 );
//  putBits(des ,0x0 , 0x8 , value1);
    //cout <<"\n The value of des is "<<des <<endl;
 
//  putBits(des , 0x8 , 0x8 , value2);
//  cout<<"\n The value of des is "<<des <<endl;
    return 0;
}

THe problem is whenever I increment a char pointer its incrementing by one byte..how do I move to the next offset value which is in bits..

[weaknessforcats]

Any time you inecrment a pointer the address it contains chnages by the soxe of the object pointed at. So the address inside your char pointer is increased byt eh sizeof(char) when you increment.

To move among the bits,use the bit shift operators << and >>.