is there any way to use macro to specialization a template class...

[kuangye]

#include <iostream>
using namespace std;

template<const int i1>
class TC
{
public:
void fn()
{
cout<<"i1 "<<i1<<endl;
}
};

const int gck = 0;
#define TC<gckDTC;//error,why?.........................
//...................
//any other solution for this except for typedef

//typedef TC<gckDTC;//ok

void try1()
{
DTC obj1;
obj1.fn();
{
const int gck = 1;
DTC obj1;
obj1.fn();
}
}
int main()
{
try1();
return 1;
}

[=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?=]

On 2007-10-23 13:09, kuangye wrote:

I do not like macros and tend not to use them so I do not know the
specifics of why this works and yours does not. But notice how macros
are defined, the identifier first and then what it should expand to.

#include <iostream>
using namespace std;

const int gck = 0;
#define DTC TC<gck// Notice that DTC comes before TC<gck>

>
template<const int i1>
class TC
{
public:
void fn()
{
cout<<"i1 "<<i1<<endl;
}
};
void try1()
{
DTC obj1;
obj1.fn();
{
const int gck = 1;
DTC obj1;
obj1.fn();
}
}
int main()
{
try1();
return 1;
}

--
Erik Wikström

[tragomaskhalos]

On Oct 23, 12:09 pm, kuangye <[e-mail]:

>
template<const int i1>
class TC
{
public:
void fn()
{
cout<<"i1 "<<i1<<endl;
}
};

const int gck = 0;
#define TC<gckDTC;//error,why?.........................
//...................
//any other solution for this except for typedef

//typedef TC<gckDTC;//ok

Your request is bizarre because the typedef mechanism
that you identify is superior in every regard to the
macro you want to replace it with !