On Thu, 18 Oct 2007 06:31:17 -0000, Rakesh UV <uv******@gmail.com>
wrote in comp.lang.c:
Hi,
If i am not putting the function prototype of a function
returning a pointer, i get a core dump.Though this will happen less
probably on 32 bit machine
example
int main(int argc , char **argv)
{
char *base = basename(argv[0]) ;
If your compiler does not issue a diagnostic for this code, either it
is badly broken, or you did not tell it to operate as an actual C
compiler. A diagnostic is required.
printf("%s",base);
return 0;
}
The compiler assumes that basename is returning an int and thus we
loose 32 bit of the actual address, because pointer is 64 bit and
integer is 32 bit in 64 bit machines
And what if 64 bit addresses are returned in a completely different
manner and you are really losing all 64 bits of the address?
I am working on
Os linux x86_64 2.6.9
Machine Hp
compiler gcc 3.46
Is there any option in GCC to make the default return value as long so
Why? The code has undefined behavior. It is wrong. It is garbage.
that i can preserve the actual address returned
or
What if 64 bit long long is returned in a different register than a 64
bit pointer?
do we have any other way in C to make it right
There is no way in C to make it right. The code has undefined
behavior. If a function returns anything other than an int, and you
do not have a prototype in scope, they there is no way to avoid
undefined behavior. Period. The only way to make it right is to have
a prototype in scope. Period.
I know that putting the prototype would solve the problem, but
unfortunately
there are huge number of files
That's why there are programs that can search and replace in huge
numbers of files.
Rakesh UV
Don't EVER port code this bad to another platform without fixing it.
And reeducate the programmers who wrote it. If they won't accept
reeducation, fire them.
--
Jack Klein
Home:
http://JK-Technology.Com
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