char and int input

[maher5]

hi

i wrote a program to convert int to binarys, it works just fine until the input is a char. how can i make it know the input is a char and not an int and therfore display and error msg?


it might be an easy q? but im only new to programming.

thanks a lot.

[Ganon11]

Are you using C or C++?

[weaknessforcats]

It appears you have it working with an int. Yes?

If so, it should work with a char. Just move your chaer to an int either directly or use the char in the call to your function with an int argument.

I guess I'm not seeing the problem. A char is just another integer.

[maher5]

it is C

and my problem is when ever a char is entered the porgram would crash
thats my codings
note: it is not an assignment so i figured i can insert the codes


#include "stdafx.h"
int _tma
in(int argc, _TCHAR* argv[])
{
int input;
printf("NOTE: To Exit Enter 9999\n");
do {
printf ("Enter Int:\n");
scanf("%d", &input);
unsigned int mask =2147483;
int i=0;
for (i=0;i<32;i++) {
int itemp=0;
itemp = (input&mask);
if (itemp != 0) {
printf ("1");
}else {
printf ("0");
}
mask = mask/2;
}
printf("\n");
}while (input!=9999);

return 0;

}


thanks a lot

[maher5]

all i want is to be able to print an error msg whenever a char is entered and not crash.. thanks again

[weaknessforcats]

int input; <<<<<<
printf("NOTE: To Exit Enter 9999\n");
do {
printf ("Enter Int:\n");
scanf("%d", &input);

You bug is where the <<< are.

A char, like A is not an in integer value. scanf() expects integer values like 19 or -98. You would need to enter 65 instead to get the A.

If you change your input to a char it will work for characters but will now crash in integers.

scanf() assumes you know the format of the data before it is entered. If you can't tell whether a user will enter digits or characters then you can't use
scanf().

You have have to get a byte at a time and analyze the result.