What Can I do with "ostream"

[LewGun]

Usually， when we program with C++, we like to include the
header"iostream", but it's too big, so i want to use the header
"ostream" (only use it to output), as follows ,there is a
piece of code what i think can do this.. but the compiler can't give
me a good news. what can i do.

//------------------------------------------------------------------
// source code
//------------------------------------------------------------------
#include <ostream>
int main(int argc, char **argv)
{
ostream os;

int forTest1 = 1;
char forTest2 = '1';
os << forTest << " " << forTest2 << "\n";

return 0;
}

// ps: compiler : VS2003.net

[Chris ( Val )]

On Oct 5, 11:12Â*pm, "[e-mail]" <[e-mail]:

Usually， when we Â* program with C++, we like to include the
header"iostream", but it's too big, so i want to use the header
"ostream" Â* Â*(only use it to output), as follows ,there is a
piece of code what i think can do this.. but the compiler can't give
me a good news. Â*what can i do.

//------------------------------------------------------------------
// source code
//------------------------------------------------------------------
#include <ostream>

int main(int argc, char **argv)
{
ostream os;

std::ostream& os( std::cout );

Alos note that you did not specify a
namespace in your code.

--
Chris Val

[=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?=]

On 2007-10-05 15:24, Chris ( Val ) wrote:

On Oct 5, 11:12 pm, "[e-mail]" <[e-mail]:

>Usually， when we program with C++, we like to include the
header"iostream", but it's too big, so i want to use the header
"ostream" (only use it to output), as follows ,there is a
piece of code what i think can do this.. but the compiler can't give
me a good news. what can i do.

//------------------------------------------------------------------
// source code
//------------------------------------------------------------------
#include <ostream>

int main(int argc, char **argv)
{
ostream os;

std::ostream& os( std::cout );

Also not that std::cout is declared in <iostream>.

To the OP: In what way is <iostreamto large? If it is you can either
use <fstreamand write to a file, or use <cstdioand use the C
functions to write to stdout.

--
Erik Wikström

[James Kanze]

On Oct 5, 3:12 pm, "[e-mail]" <[e-mail]:

Usually， when we program with C++, we like to include the
header"iostream", but it's too big, so i want to use the header
"ostream" (only use it to output), as follows ,there is a
piece of code what i think can do this.. but the compiler can't give
me a good news. what can i do.

//------------------------------------------------------------------
// source code
//------------------------------------------------------------------
#include <ostream>

int main(int argc, char **argv)
{
ostream os;

int forTest1 = 1;
char forTest2 = '1';
os << forTest << " " << forTest2 << "\n";

return 0;
}

// ps: compiler : VS2003.net

With just an ostream, you can't do very much; you need an
ofstream, or something along those lines. But because ofstream
derives from ostream, most of the source code doesn't need to
know about it. So typically, you'll #include <iostreamand
<fstreamin main, or in whatever function evaluates the command
line args, and <ostreameverywhere else (and just <iosfwdin
your headers).

--
James Kanze (GABI Software) email:ja*********@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientierter Datenverarbeitung
9 place Sémard, 78210 St.-Cyr-l'École, France, [phone]

[Chris ( Val )]

On Oct 6, 12:57Â*am, Erik Wikström <[e-mail]:

On 2007-10-05 15:24, Chris ( Val ) wrote:

On Oct 5, 11:12 pm, "[e-mail]" <[e-mail]:

Usually， when we Â* program with C++, we like to include the
header"iostream", but it's too big, so i want to use the header
"ostream" Â* Â*(only use it to output), as follows ,there is a
piece of code what i think can do this.. but the compiler can't give
me a good news. Â*what can i do.

//------------------------------------------------------------------
// source code
//------------------------------------------------------------------
#include <ostream>

int main(int argc, char **argv)
{
ostream os;

std::ostream& os( std::cout );

Also not that std::cout is declared in <iostream>.

[snip]

My apologies, I was completely focused on the syntax :-)

Thanks for the correction.

--
Chris Val