Ice Cream Problem

[audiokarate]

Hey everyone, Ok, this problem is giving me some trouble. I got it to iterate but I want it to generate an error message if a user types in an incorrect choice. I got the error message down however I think something may wrong with my do-while loop. It wont execute properly. Whenever I want to perform another transaction, my error message pops up. Any help will be appreciated.

#include <iostream>
#include <iomanip>
using namespace std; 
 
 
int main()
{
 
    cout <<setprecision(2)
        <<setiosflags(ios::fixed)
        <<setiosflags(ios::showpoint);
 
 
    char choice,
         stop;
 
    double choco_D = 0.50,
            van_S = 0.50,
            straw_B = 0.65;
 
     double num_needed = 0;
 
 
    do
    {
    cout << "\t********************************************************\n";
    cout << "            Welcome to Rainbow Ice Cream                   \n";
    cout << "\t========================================================\n";
    cout << "\t C - Chocolate Deluxe                         **\n";
    cout << "\t V - Vanilla Special                         **\n";
    cout << "\t S - Strawberry Burst                         **\n";
    cout << endl;
    cout << "\t      Please select your flavor of Ice Cream: ";
    choice = cin.get();
    cout << "\n\n";
 
    switch (choice)
    {
    case 'C':
        cout << "\t You have chosen Chocolate Deluxe\n\n";
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
        cout << "\t" << num_needed << " Chocolate Deluxe, $" <<  (num_needed * choco_D)<< "\n\n";
        break;
    case 'V':
        cout << "\t You have chosen Vanilla Special\n\n";
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
        cout << "\t" << num_needed << " Vanilla Special, $" << (num_needed * van_S) << "\n\n";
        break;
    case 'S': 
        cout << "\t You have chosen Strawberry Burst\n\n" ;
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
        cout << "\t" << num_needed << " Strawberry Burst, $" << (num_needed * straw_B) << "\n\n" ;
        break;
    default:
        cout << "\t Not a valid choice! Please enter again.: ";
        cin >> choice;
        break;
    }
 
 
 
 
 
 
    cout << "\n\nWould you like to process another transaction (Y/Z)?: ";
    cin >> stop;
    cout << "\n\n";
    }
    while(stop != 'Z'); 
 
 
    return 0;
}

[kaioshin00]

Hey everyone, Ok, this problem is giving me some trouble. I got it to iterate but I want it to generate an error message if a user types in an incorrect choice. I got the error message down however I think something may wrong with my do-while loop. It wont execute properly. Whenever I want to perform another transaction, my error message pops up. Any help will be appreciated.






#include <iostream>
#include <iomanip>
using namespace std;


int main()
{

cout <<setprecision(2)
<<setiosflags(ios::fixed)
<<setiosflags(ios::showpoint);


char choice,
stop;

double choco_D = 0.50,
van_S = 0.50,
straw_B = 0.65;

double num_needed = 0;


do
{
cout << "\t*********************************************** *********\n";
cout << " Welcome to Rainbow Ice Cream \n";
cout << "\t=============================================== =========\n";
cout << "\t C - Chocolate Deluxe **\n";
cout << "\t V - Vanilla Special **\n";
cout << "\t S - Strawberry Burst **\n";
cout << endl;
cout << "\t Please select your flavor of Ice Cream: ";
choice = cin.get();
cout << "\n\n";

switch (choice)
{
case 'C':
cout << "\t You have chosen Chocolate Deluxe\n\n";
cout << "\t Please enter the number of Ice creams needed: ";
cin >> num_needed;
cout << "\t" << num_needed << " Chocolate Deluxe, $" << (num_needed * choco_D)<< "\n\n";
break;
case 'V':
cout << "\t You have chosen Vanilla Special\n\n";
cout << "\t Please enter the number of Ice creams needed: ";
cin >> num_needed;
cout << "\t" << num_needed << " Vanilla Special, $" << (num_needed * van_S) << "\n\n";
break;
case 'S':
cout << "\t You have chosen Strawberry Burst\n\n" ;
cout << "\t Please enter the number of Ice creams needed: ";
cin >> num_needed;
cout << "\t" << num_needed << " Strawberry Burst, $" << (num_needed * straw_B) << "\n\n" ;
break;
default:
cout << "\t Not a valid choice! Please enter again.: ";
cin >> choice;
break;
}






cout << "\n\nWould you like to process another transaction (Y/Z)?: ";
cin >> stop;
cout << "\n\n";
}
while(stop != 'Z');


return 0;
}

After 1 iteration of the do while loop, cin either contains a Y or a Z.

Then, on the second iteration, it exectues choice = cin.get(), which takes either this Y or Z as your choice, and thus it is invalid. You need to flush cin before the loop ends. This can be done by adding:

cin.ignore(1, ' ');

before the close of the do loop.

Or you can change cin.get() to

cin >> choice;

I think either of those should work

[audiokarate]

Yah thanks, that helped. However whenever I perform another transaction and the user enters an invalid choice, the user is then prompted to enter a correct choice. When the user does so, it goes straight to asking if I want to perform another transaction. How do I get it to iterate again?

[kaioshin00]

Yah thanks, that helped. However whenever I perform another transaction and the user enters an invalid choice, the user is then prompted to enter a correct choice. When the user does so, it goes straight to asking if I want to perform another transaction. How do I get it to iterate again?

Here's a hint:

You need to keep on iterating the switch statement unless the user provides a valid choice. Right now the switch statement that asks the user for his/her choice only iterates once per 'transaction'.

[audiokarate]

yah, thats my problem. I have no idea how to do that. Nested loop? if statement?

[kaioshin00]

yah, thats my problem. I have no idea how to do that. Nested loop? if statement?

Try this. Before you enter the switch statement, ensure that choice is either C, V, or S.

So some pseudo code would be as follows:

while (choice isn't C V or S) {
get choice from the user
}

switch (choice) {
case C
..
case V
..
case S
..
}

[audiokarate]

 
while( choice != C || V || S)
cin >> choice;
 
 

like that?

[kaioshin00]

 
while( choice != C || V || S)
cin >> choice;
 
 

like that?

Lets think about this logically. We want the while loop that finds valid inputs to terminate if choice == C or choice == V or choice == S.

If the above is not the case, then we want to continue in order to find a valid input.

In other words, the loop should:
STOP when choice == C or choice == V or choice == S
GO if this not the case.

while (loop condition is GO) {
try and get valid value for choice from user
}


translated into C++, this is:

while ( !(choice == 'C' || choice == 'V' || choice == 'S')) {
    cout << "\t Not a valid choice! Please enter again.: ";
    cin >> choice;
}
 

Make sense?

[audiokarate]

yes that makes so much sense now. However now when I prompt the user

cout << "\n\nWould you like to process another transaction (Y/Z)?: ";
    cin >> stop;
    cout << "\n\n";
    }
    while(stop != 'Z'); 
 
 

it won't stop iterating when I type 'Z'. It just iterates again.

[kaioshin00]

yes that makes so much sense now. However now when I prompt the user

cout << "\n\nWould you like to process another transaction (Y/Z)?: ";
    cin >> stop;
    cout << "\n\n";
    }
    while(stop != 'Z'); 
 
 

it won't stop iterating when I type 'Z'. It just iterates again.

Can you post your whole code?

[audiokarate]

#include <iostream>
#include <iomanip>
using namespace std; 
 
 
int main()
{
 
    cout <<setprecision(2)
        <<setiosflags(ios::fixed)
        <<setiosflags(ios::showpoint);
 
 
    char choice,  
        stop;
 
    double choco_D = 0.50,
            van_S = 0.50,
            straw_B = 0.65;
 
    double orderC = 40;
    double orderV = 50;
    double orderS = 35;
 
     double num_needed = 0;
 
 
    do
    {
    cout << "\t********************************************************\n";
    cout << "            Welcome to Rainbow Ice Cream                   \n";
    cout << "\t========================================================\n";
    cout << "\t C - Chocolate Deluxe                         **\n";
    cout << "\t V - Vanilla Special                         **\n";
    cout << "\t S - Strawberry Burst                         **\n";
    cout << endl;
    cout << "\t      Please select your flavor of Ice Cream: ";
    cin >> choice;
    cout << "\n\n";
 
      while ( !(choice == 'C' || choice == 'V' || choice == 'S')) 
      {
          cout << "\t Not a valid choice! Please enter again.: ";
          cin >> choice;
      }
 
 
    switch (choice)
    {
    case 'C':
        cout << "\t You have chosen Chocolate Deluxe\n\n";
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
        cout << "\t" << num_needed << " Chocolate Deluxe, $" <<  (num_needed * choco_D)<< "\n\n";
        break;
    case 'V':
        cout << "\t You have chosen Vanilla Special\n\n";
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
        cout << "\t" << num_needed << " Vanilla Special, $" << (num_needed * van_S) << "\n\n";
        break;
    case 'S': 
        cout << "\t You have chosen Strawberry Burst\n\n" ;
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
        cout << "\t" << num_needed << " Strawberry Burst, $" << (num_needed * straw_B) << "\n\n" ;
        break;
    }
 
 
 
 
    cout << "\n\nWould you like to process another transaction (Y/Z)?: ";
    cin >> stop;
    cout << "\n\n";
    }
    while(stop == 'Z'); 
 
       return 0;
}
 

[kaioshin00]

Line 77 says

while(stop == 'Z')

You would want to change that to !=

[audiokarate]

the variables orderC etc are for tracking inventory. The numbers next to it is the amount of ice cream I have in stock. She wants to track it and display how much ice cream is left and display if there is no more in stock. Just so you know. At the end I have to display a sales report showing SOLD, IN STOCK, NEEDED, SALES and PROFIT. The calculations go after the loop correct?

[audiokarate]

I am having trouble coming up with and placing the calculations for the Sales report on the bottom of the program. Help?

#include <iostream>
#include <iomanip>
using namespace std; 
 
 
int main()
{
 
    cout <<setprecision(2)
        <<setiosflags(ios::fixed)
        <<setiosflags(ios::showpoint);
 
 
    char choice,  
        stop;
 
    double choco_D = 0.50,
            van_S = 0.50,
            straw_B = 0.65;
 
    double stock_C = 0;
    double stock_V = 0;
    double stock_S = 0;
 
     int num_needed = 0;
 
 
    do
    {
    cout << "\t********************************************************\n";
    cout << "            Welcome to Rainbow Ice Cream                   \n";
    cout << "\t========================================================\n";
    cout << "\t C - Chocolate Deluxe                         **\n";
    cout << "\t V - Vanilla Special                         **\n";
    cout << "\t S - Strawberry Burst                         **\n";
    cout << endl;
    cout << "\t      Please select your flavor of Ice Cream: ";
    cin >> choice;
    cout << "\n\n";
 
      while ( !(choice == 'C' || choice == 'V' || choice == 'S')) 
      {
          cout << "\t Not a valid choice! Please enter again.: ";
          cin >> choice;
      }
 
 
 
 
 
 
 
    switch (choice)
    {
    case 'C':  // CHOCOALTE DELUXE OPTION
        cout << "\t You have chosen Chocolate Deluxe\n\n";
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
 
        if(num_needed < 40)
            cout << "\t " << num_needed << " Chocolate Deluxe, $" << (num_needed * choco_D) << "\n\n";
            else
                cout << "Sorry! Out of Stock!\n";
            break;
 
 
 
    case 'V':  // VANILLA SPECIAL OPTION
        cout << "\t You have chosen Vanilla Special\n\n";
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
 
        if(num_needed < 50)
            cout << "\t" << num_needed << " Vanilla Special, $" << (num_needed * van_S) << "\n\n";
            else
            cout << "Sorry! Out of Stock!\n";
        break;
 
 
 
 
    case 'S': // STRAWBERRY BURST OPTION
        cout << "\t You have chosen Strawberry Burst\n\n" ;
        cout << "\t Please enter the number of Ice creams needed: ";
        cin >> num_needed;
 
        if(num_needed < 35)
            cout << "\t" << num_needed << " Strawberry Burst, $" << (num_needed * straw_B) << "\n\n"; 
            else 
            cout << "Sorry! Out of Stock!\n";
        break;
    }
 
 
 
 
    cout << "\n\nWould you like to process another transaction (Y/Z)?: ";
    cin >> stop;
    cout << "\n\n";
    }
    while(stop != 'Z'); // END DO-WHILE LOOP
 
 
 
 
 
 
    //CALCULATIONS
 
 
 
    //DISPLAY REPORT
    cout <<"\n\n\n\n\n\n****************** Rainbow's Ice Cream Inventory Report: ******************\n\n";
    cout << setw(28)<< "Sold" << setw(12) << "In Stock" << setw(12) << "Needed" << setw(12) << "Sales" << setw(12) << "Profit\n\n";
    cout <<"Chocolate Deluxe\n";
    cout <<"Vanilla Special\n";
    cout <<"Strawberry Burst\n\n";
    cout <<"Grand Total\n\n";
 
 
 
 
 
 
    return 0;
}
 
 

[kaioshin00]

What does your sales report need to include?