problem with reading multiple files

[anjanaanupindi]

I have the following problem: My program is supposed to read data from files to an array. The files are numbered: capture[1].bmp,capture[2].bmp and so on. And I really don't want to do the same step for so many times. Is there a way to write a loop along the lines of

for (int i=1; i<25, i++);
{
fopen ("C:\capture[i].bmp","r")
fread(ch,sizeof(ch),1,fp);
.....
}

In other words, is there a way to insert the "i" variable into the filename?

Thank you for your insights.

[ilikepython]

I have the following problem: My program is supposed to read data from files to an array. The files are numbered: capture[1].bmp,capture[2].bmp and so on. And I really don't want to do the same step for so many times. Is there a way to write a loop along the lines of

for (int i=1; i<25, i++);
{
fopen ("C:\capture[i].bmp","r")
fread(ch,sizeof(ch),1,fp);
.....
}

In other words, is there a way to insert the "i" variable into the filename?

Thank you for your insights.

Yes, there is:

fopen ("C:\capture[" + i + "].bmp", "r");
 

[anjanaanupindi]

Yes, there is:

fopen ("C:\capture[" + i + "].bmp", "r");
 

thank you...................but i f i do that it's showing an error like



expression must have integral type
fopen ("C:\capture[" + i + "].bmp", "r");


actually wht is that + i + operator..............to use that we have to include any headre file

[sicarie]

thank you...................but i f i do that it's showing an error like



expression must have integral type
fopen ("C:\capture[" + i + "].bmp", "r");


actually wht is that + i + operator..............to use that we have to include any headre file

I believe your error is being caused by an int being inserting into a string, I would recommend using a stringstream to convert the int to a char/string that can then be used in that fashion.

[weaknessforcats]

Your file isn't opening. Since you don't check that, you wouldn't know.

The problem is the path. \c is a carriage return and not two characters \ and c.

Try

fopen ("C:\\capture[i].bmp","r");
 

Besides you didn't have a ; at the end of your fopen si the code may not have compiled at all.

The next thing is to get the [i] outdside the literal (see Post #2).

[anjanaanupindi]

Your file isn't opening. Since you don't check that, you wouldn't know.

The problem is the path. \c is a carriage return and not two characters \ and c.

Try

fopen ("C:\\capture[i].bmp","r");
 

Besides you didn't have a ; at the end of your fopen si the code may not have compiled at all.

The next thing is to get the [i] outdside the literal (see Post #2).

Thank You for ur suggetion...........

but if i do the same also same thing means it's opening the file but it's not reading any thing from file


fopen ("C:\\capture[k].bmp", "r");


fread(&ch,sizeof(ch),1,fp);

fclose(fp);

[weaknessforcats]

fopen ("C:\\capture[k].bmp", "r");

Your file is not opening because the file name is not C:\capture[k].bmp.

Its probably something like C:\capture25.bmp

So you need to build the file name correctly.

Apparently you are using C:

char* filename[80];
filename[0] = '\0';
strcat(filename, "C:\\capture");
strcat(filename, k + '0');     //convert the int to a char
strcat(filename, ".bmp");
FILE* f = fopen(filename, "r");
if (f == NULL)
{
     printf("file did not open\n");
     exit(1);
}