How to check conent in char.

[recordlovelife]

Very simply, I want to compare the value of a user entered data to a given value, and have that set a value of another variable. In theory, something like this....

char x;
int y;
cin>>x;
if(x="a"){y=1;}
 

But that doesn't work. I'm pretty sure it's because C++ can't tell what you have in a char variable, it can just spit it back at you. What can i do to make my concept work.

[Savage]

Very simply, I want to compare the value of a user entered data to a given value, and have that set a value of another variable. In theory, something like this....

char x;
int y;
cin>>x;
if(x="a"){y=1;}
 

But that doesn't work. I'm pretty sure it's because C++ can't tell what you have in a char variable, it can just spit it back at you. What can i do to make my concept work.

What can you do?

Only thing you need to do is to replace " with '...

Savage

[recordlovelife]

Hahah, ::bows head in shame::

Thank you for the quick response.

[Banfa]

Only thing you need to do is to replace " with '...

and replace = with ==

[Savage]

and replace = with ==

Didn't saw that..

Savage

[JosAH]

Very simply, I want to compare the value of a user entered data to a given value, and have that set a value of another variable. In theory, something like this....

char x;
int y;
cin>>x;
if(x="a"){y=1;}
 

But that doesn't work. I'm pretty sure it's because C++ can't tell what you have in a char variable, it can just spit it back at you. What can i do to make my concept work.

Chars are not strings and leaving the value of a local variable undefined in one
branch of the control flow is a dangerous thing to do; do this instead:

char x;
int y;
cin>>x;
y= (x == 'a');
 

Note the single quotes and also note that (local variable?) y equals either 1 or 0
according to the value of x.

kind regards,

Jos

[recordlovelife]

Chars are not strings and leaving the value of a local variable undefined in one
branch of the control flow is a dangerous thing to do; do this instead:

char x;
int y;
cin>>x;
y= (x == 'a');
 

Note the single quotes and also note that (local variable?) y equals either 1 or 0
according to the value of x.

kind regards,

Jos

I don't know if your method will work for what I am trying to do, but I may be wrong- so please clarify.

For my example, i am trying to make a loop based on user input, but the user may enter a letter or a number, so i was doing something like this.

int loopPicker;
int x;
char y;
int z;
 
cout<<"type 1 for number, 2 for letter";
cin>>loopPicker;
 
while(loopPicker=1)
{
    cout<<"enter a number:";
    cin>>x;
 
cout<<"type 1 for number, 2 for letter";
cin>>loopPicker;
}
 
while(loopPicker=2)
{
    cout<<"enter a letter:";
    cin>>y;
 
if(y=='a'){z=10)
if(y=='b'){z=11)
if(y=='c'){z=12)
          .
          .
          . 
    //and so on.
 
cout<<"type 1 for number, 2 for letter";
cin>>loopPicker;
}
 

but 2 probs..
1)i need an

if(y!=='a'||y!=='b'.......){cout<<"bad input";}

not working.

2)loopPicker wont swtch to second loop, stays on loop 1 regardless of if you type "2" for a loop choice.

please help, you guys rock