Formatting C output

[ShawnRR]

Hi all,

This program is an easy "printing" Calculator... the problem i am having is that when I type in "0e" or "0E" for the program to exit it thinks i am typing in an exponent value and does not exit unless i type in "0ee" or "0EE". My question is how do i change this code around so when i type in "0e" or "0E" it exits the program.

Here is the code:

// Program 6-4 Simple printing calculator NOTE: Program won't accept "e" or "E" preceded
// by a number because it thinks "e" stands for power of. Ex 10e12
 
#include <stdio.h>
#pragma warning (disable: 4996)
 
int main (void)
{
    float accumulator = 0.0f, number = 0.0f;
    char oper = ' ';
 
    printf ("Begin Calculations\n");
 
    do{
        scanf ("%f %c", &number, &oper);
 
        switch (oper)
        {
            case 'S':
            case 's':
                accumulator = number;
                printf("%f    content of accumulator\n", accumulator);
                break;
 
            case '/':
                if ( number == 0)
                    printf ("Dividing by 0!\n");
                                        break;
                else
                    printf("%f    content of accumulator\n", accumulator = accumulator / number);
                break;
 
            case '*': 
                printf("%f    content of accumulator\n", accumulator = accumulator * number);
                break;
 
            case '+':
                printf("%f    content of accumulator\n", accumulator = accumulator + number);
                break;
 
            case '-':
                printf("%f    content of accumulator\n", accumulator = accumulator - number);
                break;
 
            case 'e':
            case 'E':
                break;
 
            default:
                printf ("Unkown operator!\n");
                break;
        }
    }
    while ( oper != 'E' && oper != 'e' );
 
        printf ("End of calculations.\n");
 
    return 0;
 
}
 

The current output looks like this

Begin Calculations
22s
22.000000       content of accumulator
5 -
17.000000       content of accumulator
22 e
End of calculations.
Press any key to continue . . .
 

I would like to make it look like this:

Begin Calculations
22s                 Set Accumulator to 22 (Print this line on the same line as input)
22.000000       content of accumulator
5 -                  Subtract 5
17.000000       content of accumulator
22 e               End of program
End of calculations.
Press any key to continue . . .
 

Basically what I am asking is how do I make the program print a line of text on the same line of the user input line or the scanf line.

[Savage]

::snipped quote so post will show::


Wait a second what is your problem:

1.) To get 0e to exit the program or
2.) To print the text on the same line where user inputs data?

Savage

[sicarie]

Basically what I am asking is how do I make the program print a line of text on the same line of the user input line or the scanf line.

Don't using newline characters ('\n') in your output strings where you want to have something after it.

[ShawnRR]

::snipped quote so post will show::


Wait a second what is your problem:

1.) To get 0e to exit the program or
2.) To print the text on the same line where user inputs data?

Savage

Savage,

My problem is both. I want the program to exit when i type 0e and also i want to be able to output with printf on the same line where i input with scanf.

thanks
shawn

[Savage]

Savage,

My problem is both. I want the program to exit when i type 0e and also i want to be able to output with printf on the same line where i input with scanf.

thanks
shawn

If you want it to exit when e is typed,you will need to store number in a char array,search for the occurrence of e and if any then exit.Second problem has been answered by sicarie.

Savage

[RRick]

You're problem lies with scanf and reading %f, i.e. a float. Since floats can take an exponential, scanf is going to consume any 0e you send it and convert it into a float.

Why not make the "break" command a q? Scanf will never read a 'q' into a float.

[ShawnRR]

If you want it to exit when e is typed,you will need to store number in a char array,search for the occurrence of e and if any then exit.Second problem has been answered by sicarie.

Savage

Savage the only problem with Sicarie's answer is that scanf automatically seems to continue to the next line when user inputs his value. I know how to make the printf print on the same line before the user input but i want to printf on the same line after the user input. Also on storing number in a char array can you give me a sample code on how i would than do the arithmetic operation using that char array since the user inputed numbers are stored as symbols and not as actual numbers.

Thanks

[ShawnRR]

You're problem lies with scanf and reading %f, i.e. a float. Since floats can take an exponential, scanf is going to consume any 0e you send it and convert it into a float.

Why not make the "break" command a q? Scanf will never read a 'q' into a float.

RRick,

I totally agree with you except that the programming exercise specifically asks to use E or e as the break point.

[Savage]

Savage the only problem with Sicarie's answer is that scanf automatically seems to continue to the next line when user inputs his value. I know how to make the printf print on the same line before the user input but i want to printf on the same line after the user input. Also on storing number in a char array can you give me a sample code on how i would than do the arithmetic operation using that char array since the user inputed numbers are stored as symbols and not as actual numbers.

Thanks

Use wherey and wherex functions to remember current coordinated,and then just after scanf reduce y for one and use gotoxy(x,y) to return to the previos line.

About your second question,you can use atoi to convert form char[] to int,enabling you to do anything with it.

Savage

[RRick]

Shawn,

You're going to have to get rid of the %f in your scanf or else put a space between the number and command in your input.

If you can't put in a space for the command, then read everything into a char buffer and extract the command before you parse for the float.