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Postfix and Prefix operator with respect to functions

P: 21

In I read about postfix and prefix unary operators.

It said " If the increment or decrement operator is used as a prefix, the operation is performed before the function call. If the operator is used as a postfix, the operation is performed after the function call. "

So accordingly
int x=4;
printf("%d%d", x++,x++);
the output should be 4 4

But it is never so in C. The output would rather be 5, 4.
But it applies to C++. I tried in VC++, the postfix operation indeed is performed after the function call.

What do you guys have to say on this?
Sep 7 '07 #1
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2 Replies

Expert 2.5K+
P: 3,652
I would say what I'm sure Banfa and many other experts would say: You have invoked undefined behavior. Using pre- or post-increment operators twice in the same statement means that you cannot predict exactly what the result will be. I suspect the differences you are seeing between C and C++ might have something to do with the way your compilers interpret these statements.

Basically, don't write statements like this.
Sep 7 '07 #2

P: 21
Alright. Please consider this example.

void main()
int x=4;
func(int x, int y)
/*Some definition*/
My concern was about the statement which i quoted in my prevoius post.According to it, the calling func() would pass 4 and 4 not 5 and 4.

Like i mentioned before,when i ran this in MSVC++6.0 , it is passing 4 and 4 not 5 and 4. I was wondering if there is really a difference for increment and decrement operators when it comes to different programming languages.(c, c++).

I am convinced with the way increment and decrement operators work in C.
That statement just made me curious.
Sep 8 '07 #3

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