How can I pass an array of pointers to stuctures?

[UncleRic]

Does anyone know how to return a usable array of pointers to structures?

Here's the structure:

typedef struct {
    char* name;   //  '\0'-terminated C string 
    int   number;
} SomeSeq;
 

I know I can do this:

 
    ...
    int n = 2;
    SomeSeq myStruct[n];
    myStruct[0].name = "Ric\0";
    myStruct[0].number = 5;
    ...
 

Now I want to create a function that returns myStruct[n] where 'n' is variable.
Here's my attempt:

struct *myFunction() {
    .... // computing the value of 'n'...
    return myStruct[n];
}
 

I'm not quite sure of the syntax here.

Regards,

Ric (lost Neophyte)

[RRick]

In your function, myStruct[n] refers to a SomeSeq, not a SomeSeg*. To return a pointer to SomeSeq, define the function as:

struct SomeSeq *  myFunction()

and have the function

return & myStruct[n];

[weaknessforcats]

To the OP:

Be sure you don't return the address of a local variable since that variable will be destroyed when the function completes.