Reg. strncmp

[arunraj2002in]

Hi All,

I have doubt in strncmp.
consider the following prog:

int main()
{

int i;
i = strncmp("Nstring","Astring",6);
printf("%d", i);
}

Here o/p is 13, now if i modify the prog like:

i = strncmp("Nstrisg","Astring",6); O/P is 5 why??

ok ok.. got it !! while typing the question i got the ANSWER.
it print the difference in the character.. Right?

[JosAH]

Hi All,

I have doubt in strncmp.
consider the following prog:

int main()
{

int i;
i = strncmp("Nstring","Astring",6);
printf("%d", i);
}

Here o/p is 13, now if i modify the prog like:

i = strncmp("Nstrisg","Astring",6); O/P is 5 why??

ok ok.. got it !! while typing the question i got the ANSWER.
it print the difference in the character.. Right?

That would clarify the first comparison: 'N'-'A' == 13 but what about the second
comparison then? It seems as if strncmp compares starting at the last character:
's'-'n' == 5 but that isn't a valid way to compare two strings lexicographically.

kind regards,

Jos

[arunraj2002in]

That would clarify the first comparison: 'N'-'A' == 13 but what about the second
comparison then? It seems as if strncmp compares starting at the last character:
's'-'n' == 5 but that isn't a valid way to compare two strings lexicographically.

kind regards,

Jos

OOps typing mistake.. Sorry man.. its:
i = strncmp("Nstrisg","Nstring",6); now for i = strncmp("Nstrisg","Astring",6);
Answer is 13 only..

[JosAH]

OOps typing mistake.. Sorry man.. its:
i = strncmp("Nstrisg","Nstring",6); now for i = strncmp("Nstrisg","Astring",6);
Answer is 13 only..

Ah, ok, that explains it all: the diference of the two characters that are not equal
is the return value of the strncmp function: 'N'-'A' == 13 and 's'-'n' == 5.

kind regards,

Jos