C++ Primer ex 7.15 ambiguous statement

[arnuld]

STATEMENT: write a main function that takes two vales as arguments and
print their sum.
the main takes classic arguments ;) int main( int argc, char **argv )

1st argument is an int while 2nd argument is an array of string literals.
how am i supposed to add a string literl to an int ?


--
http://arnuld.blogspot.com

[Gianni Mariani]

arnuld wrote:

STATEMENT: write a main function that takes two vales as arguments and
print their sum.
the main takes classic arguments ;) int main( int argc, char **argv )

1st argument is an int while 2nd argument is an array of string literals.
how am i supposed to add a string literl to an int ?

Maybe convert the strings to an int ?
int x = Convert( "-122" );
int y = Convert( "122" );

int sum = x + y;

??

What does Convert look like ?

What does Convert( "Google" ) do ?

[Daniel T.]

In article <pa****************************@gmail.com>,
arnuld <ge*********@gmail.comwrote:

STATEMENT: write a main function that takes two vales as arguments and
print their sum.
the main takes classic arguments ;) int main( int argc, char **argv )

1st argument is an int while 2nd argument is an array of string literals.
how am i supposed to add a string literl to an int ?

Try this:

int main( int argc, char* argv[] )
{
for ( int i = 0; i < argc; ++i )
cout << argv[i] << '\n';
}

Then run your program using:

program 1 2

You should end up with the following output:

program
1
2

Now all you have to do is figure out how to add the 1 and 2 to produce 3
and output it instead.