Printing the diagonal elements of an array using for loop..

[balaraja]

Hi
how to print the diagonal elements of a two dimensional array using for loop
Can any one help me...Plzzzzzzzz..

Thanks in advance
Bala...

[JosAH]

Hi
how to print the diagonal elements of a two dimensional array using for loop
Can any one help me...Plzzzzzzzz..

Thanks in advance
Bala...

Just think a bit: what is characteristic about the index values of the elements
on the diagonal of a matrix? And what is 'Plzzzzzz'? Keyboard got stuck?

kind regards,

Jos

[Girish Kanakagiri]

Hi
how to print the diagonal elements of a two dimensional array using for loop
Can any one help me...Plzzzzzzzz..

Thanks in advance
Bala...

develop one for loop for row traversing in the array and
inside this nest another for loop for column traversing within
the row.

In side the inner for loop just check whether row value and
column value are equal; if yes then print the array element
with row and column subscripts.

Do you feel you got the solution or still struggling ?

Regards,
Girish.

[Gauri attal]

Hi
how to print the diagonal elements of a two dimensional array using for loop
Can any one help me...Plzzzzzzzz..

Thanks in advance
Bala...

Hi,

Try out this ....


for(int i=0;i<3;i++)
{
for (int j=0;j<=i;j++)
{
if(i==j)
{
cout<<"the diagonal elements are"<<a[i][j];
}
}
}

U too could have even tried...anyways...try the above

Gauri.

[JosAH]

Hi,

Try out this ....

<code snipped>

Better not; a nested loop is not necessary to iterate over the diagonal of a matrix.

kind regards,

Jos

[Sam Tan]

__0 1 2 3
0| 1 0 0 1 |
1| 0 1 0 1 |
2| 1 0 0 0 |
3| 1 0 1 1 |

coordinates of diagonal elements
(0,0)
(1,1)
(2,2)
(3,3)

don't you see the pattern :) ?

Sam

[emaghero]

I aggree with Josah, a single loop will do the job.

Also remember that the diagonal of a matrix (array) only makes sense if the matrix is square, ie number of rows equals number of columns.

int rows;
int columns;
 
//Assign a value to rows and columns
 
//Also assign values to the matrix
 
if(rows !=columns){
    cout<<"Cannot obtain the diagonal of a non-square matrix\n";
}
else{
     for(int i=0;i<rows;i++){
           cout<<a[i][i]<<endl;
     }
}
 

[Lestat]

Just go with the program hint given by Gauri this program

for(int i=0;i<3;i++)
{
for (int j=0;j<=i;j++)
{
if(i==j)
{
cout<<"the diagonal elements are"<<a[i][j];
}
}
}

[shikha tripathi]

but what if we want to print both the digonals????

[Banfa]

There is still a relationship between the 2 indexes you just need to work it out.

[chaitanya4b3]

I think this should work
#include<stdio.h>
int main()
{
int a[3][3],i,j,n;
scanf("%d",&n);
for(i=0;i<n;i++)
for(j=0;j<n;j++)
{

scanf("%d",&a[i][j]);


}
for(i=0;i<n;i++)
for(j=0;j<n;j++)
{
if(i==j)
{
printf("%d",a[i][j]);
}

}


}

[Mathss]

In Java,

for(int i=0; i<Arr.length; i++){
System.out.println( Arr[i][i] + " " + Arr[i][Arr.length-1-i]);
}