Address of a member function

[Neo]

hi,
I searched in the groups here but didnt find any post answering my
question. My question is I need the address of the member function in
the same class. Is there anyway to go about it other than making the
func static?
For ex:

class foo {
some_type x
void fa();
----
}

Now in its constructor-
foo::foo() {
x = <adddress_of_fa>;
}

how do I do the above?? I tried &(this->fa) but it says "C++ forbids
taking the address of a bound member function to form a pointer"
Thanks,
Neo

[Ian Collins]

Neo wrote:

hi,
I searched in the groups here but didnt find any post answering my
question. My question is I need the address of the member function in
the same class. Is there anyway to go about it other than making the
func static?
For ex:

class foo {
some_type x
void fa();
----
}

Now in its constructor-
foo::foo() {
x = <adddress_of_fa>;
}

how do I do the above?? I tried &(this->fa) but it says "C++ forbids
taking the address of a bound member function to form a pointer"

class foo {

typedef void (foo::*some_type)();

some_type x;

void fa();

foo() : x(&foo::fa) {}
};

--
Ian Collins.

[Neo]

On Aug 10, 11:22 am, Ian Collins <[e-mail]:

Neo wrote:

hi,
I searched in the groups here but didnt find any post answering my
question. My question is I need the address of the member function in
the same class. Is there anyway to go about it other than making the
func static?
For ex:

class foo {
some_type x
void fa();
----
}

Now in its constructor-
foo::foo() {
x = <adddress_of_fa>;
}

how do I do the above?? I tried &(this->fa) but it says "C++ forbids
taking the address of a bound member function to form a pointer"

class foo {

typedef void (foo::*some_type)();

some_type x;

void fa();

foo() : x(&foo::fa) {}

};

--
Ian Collins.

I have a correction-
x needs something of type void(*)() but can I pass the address
void(foo::*)() to it Or should it be a static function only?

thanks

[Gianni Mariani]

Neo wrote:

On Aug 10, 11:22 am, Ian Collins <[e-mail]:

....

I have a correction-
x needs something of type void(*)() but can I pass the address
void(foo::*)() to it Or should it be a static function only?

It must be a static function only.

[Neo]

On Aug 10, 1:25 pm, Gianni Mariani <[e-mail]:

Neo wrote:

On Aug 10, 11:22 am, Ian Collins <[e-mail]:

...

I have a correction-
x needs something of type void(*)() but can I pass the address
void(foo::*)() to it Or should it be a static function only?

It must be a static function only.

thank you.

[James Kanze]

On Aug 10, 10:22 am, Neo <[e-mail]:

On Aug 10, 11:22 am, Ian Collins <[e-mail]:

Neo wrote:

I searched in the groups here but didnt find any post answering my
question. My question is I need the address of the member function in
the same class. Is there anyway to go about it other than making the
func static?
For ex:

class foo {
some_type x
void fa();
----
}

Now in its constructor-
foo::foo() {
x = <adddress_of_fa>;
}

how do I do the above?? I tried &(this->fa) but it says "C++ forbids
taking the address of a bound member function to form a pointer"

class foo {

typedef void (foo::*some_type)();

some_type x;

void fa();

foo() : x(&foo::fa) {}

};

I have a correction-
x needs something of type void(*)() but can I pass the address
void(foo::*)() to it Or should it be a static function only?

The only thing you can use for type void(*)() is a free function
or a static function, with the correct signature.

In C++, the usual solution here would be to replace the
void(*)() with something like:

struct Callback
{
virtual ~Callback() {}
virtual void operator()() const = 0 ;
} ;

and use a Callback const*. If you have access to the sources
where the callback is used, do this. Otherwise, you're sort of
stuck.

Note too that if you pass the pointer to function to a C
function, the function itself has to be `extern "C"'. Which
means that even a static member function can't be used.

--
James Kanze (GABI Software) email:[e-mail]
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