Multi Inheritance

[Ali Karaali]

Hello group !

I have a class interface (as .h ) but i don't have this class's source
file (as .cpp ). So i can't reach the source file..

class ServerBase {
public :
virtual void vfunc() const;
void nvfunc() const;
~ServerBase();
};

class ServerDer : public ServerBase {
public :
void vfunc() const;
~ServerDer();
};

I want to make nvfunc() and ~ServerBase functions virtual. how can i
do that?

[Ali Karaali]

You can't. That is, you can't make the existing code call your nvfunc()

implementation. But you can obtain that effect for your own code, by
wrapping the class, e.g.

class MyServerBase
{
private:
virtual ServerBase& impl() = 0;
public:
virtual ~MyServerBase() {}
virtual void nvfunc() const { impl().nvfunc(); }
};

class MyServerDer: public MyServeBase
{
private:
ServerDer myImpl;
ServerDer& impl() { return myImpl; }
public:
virtual void nvfunc() cosnt { ... }
...
};

Maybe i think it can be, like this

class NewBase {
public :
virtual void vfunc() const = 0;
virtual void nvfunc() const = 0;
virtual void new_vfunc() const = 0;
virtual ~NewBase()
{
std::cout<<"NewBase::~NewBase()\n";
}
};

class Join : public NewBase , public ServerBase {
public :
void vfunc() const
{ std::cout<<"Join::vfunc() const\n"; }
void nvfunc() const
{ std::cout<<"Join::nvfunc() const\n"; }
void new_vfunc() const
{ std::cout<<"Join::new_vfunc const\n"; }
~Join()
{ std::cout<<"Join::~Join()\n"; }
};

L ke that but i don't understand explicitly? How can do that?