Simple typedef question......

[DavidKrutsko]

Hey,

is it possible to typecast inside typedef, for example:

typedef char DEF

but instead of displaying definition as a character and NOT having to typecast later on (aka DEF something = 5; cout << (int)something;)

is there any way to typecast right at the beggining at the typedef stage....

thanks,

P.S any clever alternatives to this welcome..... as long as it has the same result....

[gpraghuram]

Hey,

is it possible to typecast inside typedef, for example:

typedef char DEF

but instead of displaying definition as a character and NOT having to typecast later on (aka DEF something = 5; cout << (int)something;)

is there any way to typecast right at the beggining at the typedef stage....

thanks,

P.S any clever alternatives to this welcome..... as long as it has the same result....

Hi,
Can u explain it more with a example.
I am not ver clear with ur requirement.

Raghuram

[DavidKrutsko]

um alright well...

typedef unsigned char byte;

but of cource when i define a variable with byte it gives me characters rather than numbers for example:

------------------------------------------------------------
#include <iostream>
typedef unsigned char byte;
using std::cout;

main()
{
byte Value = 5;
cout << Value;
}
------------------------------------------------------------
BUT unless i do cout << (int)Value; i get Value's character equivelent which is a clubs icon....

so instead of type casting a bunch of times is there a way to typecase inside the typedef .... something like

typedef unsigned char (int)byte;

but this wouldent work of cource... so i was wondering if there is some way of making it work......

[gpraghuram]

um alright well...

typedef unsigned char byte;

but of cource when i define a variable with byte it gives me characters rather than numbers for example:

------------------------------------------------------------
#include <iostream>
typedef unsigned char byte;
using std::cout;

main()
{
byte Value = 5;
cout << Value;
}
------------------------------------------------------------
BUT unless i do cout << (int)Value; i get Value's character equivelent which is a clubs icon....

so instead of type casting a bunch of times is there a way to typecase inside the typedef .... something like

typedef unsigned char (int)byte;

but this wouldent work of cource... so i was wondering if there is some way of making it work......

Hi,
According to my knowledge its not feasible.

Raghuram

[DavidKrutsko]

alright thanks, ive been actually thinking about it and yeah i kinda agree.... no point since cout will only use it....

[weaknessforcats]

A coule of things.

but of cource when i define a variable with byte it gives me characters rather than numbers for

This is not true. When you typedef an unsigned char you still have an unsigned char. Next, there are three kinds of built-in variables in C/C++. There are integers, floating point and pointer variables.

An unsigned char is not a pointer or a floating point variable. So, it has to be an integer. In fact, it's just an 8-bit integer that contains integer values.

Then when you cout << achar you should see the integer value. However, the << operator with a char on the right assumes you want the ASCII glyph rather than the number. So yo get A instead of 65.

There are many << operators. The one with an int on the right assumes you want the integer value so you see 65 and not A.

All you have to do is assign your char to an int to see the numeric value.

You do not typecast.

In fact, you never typecast in C++ unless a) you a calling a relic C function, b) you are doing very low level file I/O or c) your design is faulty.