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void func(int array[32]) standard confirmed?

void func(int array[32]) {
for (int i = 0; i < 32; ++i)
cout << array[i] << ' ';
}

as the code above shows, I know int array[32] here will decay into int
*, but I still find the number 32 useful for reminding me the array len
Is this code standard confirmed?
Jul 31 '07 #1
3 2029
Barry wrote:
void func(int array[32]) {
for (int i = 0; i < 32; ++i)
cout << array[i] << ' ';
}
You could write it like so:

template <typename T, int N>
void func(T (& array)[N])
{
for (int i = 0; i < N; ++i)
cout << array[i] << ' ';
}

>
as the code above shows, I know int array[32] here will decay into int
*, but I still find the number 32 useful for reminding me the array len
Is this code standard confirmed?
It is standard.
Jul 31 '07 #2
On Jul 31, 1:27 pm, Barry <dh...@126.comwrote:
void func(int array[32]) {
for (int i = 0; i < 32; ++i)
cout << array[i] << ' ';

}
void fun(int (&array)[32])
{
// your code here
}

-N

Jul 31 '07 #3
On Jul 31, 3:14 pm, Neelesh Bodas <neelesh.bo...@gmail.comwrote:
On Jul 31, 1:27 pm, Barry <dh...@126.comwrote:
void func(int array[32]) {
for (int i = 0; i < 32; ++i)
cout << array[i] << ' ';
}

void fun(int (&array)[32])
{
// your code here

}
I wrote the above reply with a thought that you were asking for a
version of 'fun' specifically for an array of size 32. After re-
reading your post, though, I think thats not what you meant.

Anyways.
-N.
>
-N

Jul 31 '07 #4

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