Counting unique elements in an array

[aszia787]

Hi guys,

I need to count the unique elements in an array. For example, if i have an array,
array[0,0,0,1,2,3,3]. The number of unique elements in the array is 3. I am sorry if this message has been posted before. Help is appreciated. Thanks in advance.

Regards,

AZ.

[JosAH]

Hi guys,

I need to count the unique elements in an array. For example, if i have an array,
array[0,0,0,1,2,3,3]. The number of unique elements in the array is 3. I am sorry if this message has been posted before. Help is appreciated. Thanks in advance.

Regards,

AZ.

Is the array sorted, i.e. are the non-unique elements adjacent to eachother?
(that was a spoiler already, I'm sure).

kind regards,

Jos

[aszia787]

Yes, the arrays are sorted. Thanks for your reply.

AZ.

[seforo]

Actually there are 4 unique elements in your example array, zero is also a number. Since the numbers are sorted then it is simple:

#include <iostream>
using namespace std;
int main()
{
  const int size = 7;
  int array[size] = {0,0,0,1,2,3,3};
  int unique = 1; //incase we have only one element; it is unique!
  for(int i = 0; i < size -1 /*since we don't want to compare last element with junk*/; i++)
    {
     if(array[i]==array[i+1])
       continue;
     else
       unique++;
    }
  cout<<"The number of unique elements is "<<unique<<endl;
  return 0;
}
 

I hope I have not broken the laws of the scripts by giving you a fully code.

[aszia787]

Actually there are 4 unique elements in your example array, zero is also a number. Since the numbers are sorted then it is simple:

#include <iostream>
using namespace std;
int main()
{
  const int size = 7;
  int array[size] = {0,0,0,1,2,3,3};
  int unique = 1; //incase we have only one element; it is unique!
  for(int i = 0; i < size -1 /*since we don't want to compare last element with junk*/; i++)
    {
     if(array[i]==array[i+1])
       continue;
     else
       unique++;
    }
  cout<<"The number of unique elements is "<<unique<<endl;
  return 0;
}
 

I hope I have not broken the laws of the scripts by giving you a fully code.

Hi,

Thanks bro. Thx for your help. highly appreciated.

AZ.

[JosAH]

I hope I have not broken the laws of the scripts by giving you a fully code.

Well actually you have, but apparently it slipped through. Don't post full code
spoonfeeding solutions anymore. Read the Help link (top right) for the forum
posting guidelines. When I happen to pass by here and I see full code spoon-
feeding, I remove it; please don't do it again, i.e. it is not in the benefit of the OP
to cheat with homework assignments.

kind regards,

Jos