i need a code for solving operations..

[dee vee bee]

this is my project
i need a code that will show like this..
"first number __"
"second number ___"
"choose operation:
addition..subtraction..multiplication..division"
"the answer is ___"

the user will input his number,
then he will choose also what operation to use..

this is the code that i made:

#include<stdio.h>
#include<conio.h>
main()
{

int num1;
int num2;
int ans;
char oper;

printf("the first number is \n");
scanf("%d",&num1);
printf("the second number is \n);
scanf("%d",num2);
printf(choose operation: \naddition = a\n subtraction = b\n multiplication = c\n division = d\n);
scanf("%c",oper);

for (oper = a;oper = num1+num2;oper ==ans);
printf("the naswer is %d",ans);

getch();
}

im really confuse on doing this..

please help me..

[JosAH]

this is my project
i need a code that will show like this..
"first number __"
"second number ___"
"choose operation:
addition..subtraction..multiplication..division"
"the answer is ___"

the user will input his number,
then he will choose also what operation to use..

this is the code that i made:

#include<stdio.h>
#include<conio.h>
main()
{

int num1;
int num2;
int ans;
char oper;

printf("the first number is \n");
scanf("%d",&num1);
printf("the second number is \n);
scanf("%d",num2);
printf(choose operation: \naddition = a\n subtraction = b\n multiplication = c\n division = d\n);
scanf("%c",oper);

for (oper = a;oper = num1+num2;oper ==ans);
printf("the naswer is %d",ans);

getch();
}

im really confuse on doing this..

please help me..

The reading part is sort of ok (it doesn't work yet though) but it's the second
part of your code that surprises me:

for (oper = a;oper = num1+num2;oper ==ans);
printf("the naswer is %d",ans);
 

What did you have in mind when you wrote that? You have two numbers: num1
and num2; you have a character oper and according to its value you should do
something. I had a series of if - else statement in mind or a switch statement
but not a loop.

kind regards,

Jos

[Meetee]

this is my project
i need a code that will show like this..
"first number __"
"second number ___"
"choose operation:
addition..subtraction..multiplication..division"
"the answer is ___"

the user will input his number,
then he will choose also what operation to use..

this is the code that i made:

#include<stdio.h>
#include<conio.h>
main()
{

int num1;
int num2;
int ans;
char oper;

printf("the first number is \n");
scanf("%d",&num1);
printf("the second number is \n);
scanf("%d",num2);
printf(choose operation: \naddition = a\n subtraction = b\n multiplication = c\n division = d\n);
scanf("%c",oper);

for (oper = a;oper = num1+num2;oper ==ans);
printf("the naswer is %d",ans);

getch();
}

im really confuse on doing this..

please help me..

You can use case statement in this problem.

like

switch(string)
{
case addition:
do addition.......
 
case subtraction:
do subtraction...
 
etc:
} 
 

Kindly read tutorial if you want more details about switch case.

Regards

[archonmagnus]

...
printf("the second number is \n);
scanf("%d",num2);
...

Not to be picky, but I think you are missing an ampersand in your second scanf statement.