Contact List

[Hunderpanzer]

Hello,
I figured I'd make a nice program to list my contact names and phone numbers (since I keep losing my cellphone) though I have a few questions...

How would I list the strings if I wanted to be able to add contacts through the program ? Would I just have to list extra strings just in case ? I would prefer not to.


Second question
My program will list choices (A, B, and C) and get the user's input (x), telling what the program to do. I have it set up so that if the user input a, or A it would do the same thing, and same goes for the others. My problem is that if the user inputs W or something, I have an Else option, printing " come again ?" and asking for x again.

But if the user inputs W again, (or a few more times) the program just ends. I need some loop keeping the user at that state, or sending it back up to the beginning of the program.
This's what I got:

if (x == "a" || x == "A"){
       cout << "A list of contacts should appear" ;
       }
    else{
         cout << "Pardon me?  Please type that again... ";
         cin >> x;
}

apparently it's not working too well : /



Yet another question... How do I wrap the above code in C++ code ? I don't see the option anywhere.


I appreciate your time

[ilikepython]

Hello,
I figured I'd make a nice program to list my contact names and phone numbers (since I keep losing my cellphone) though I have a few questions...

How would I list the strings if I wanted to be able to add contacts through the program ? Would I just have to list extra strings just in case ? I would prefer not to.


Second question
My program will list choices (A, B, and C) and get the user's input (x), telling what the program to do. I have it set up so that if the user input a, or A it would do the same thing, and same goes for the others. My problem is that if the user inputs W or something, I have an Else option, printing " come again ?" and asking for x again.

But if the user inputs W again, (or a few more times) the program just ends. I need some loop keeping the user at that state, or sending it back up to the beginning of the program.
This's what I got:

if (x == "a" || x == "A"){
       cout << "A list of contacts should appear" ;
       }
    else{
         cout << "Pardon me?  Please type that again... ";
         cin >> x;
}

apparently it's not working too well : /



Yet another question... How do I wrap the above code in C++ code ? I don't see the option anywhere.


I appreciate your time

You could use a do while loop:

char x;
do
{
    cin >> x;
}
while (tolower(x) != 'a' && tolower(x) != 'b' && tolower(x) != 'c');
// x is either 'a', 'b', or 'c'
 

[gpraghuram]

Hello,
I figured I'd make a nice program to list my contact names and phone numbers (since I keep losing my cellphone) though I have a few questions...

How would I list the strings if I wanted to be able to add contacts through the program ? Would I just have to list extra strings just in case ? I would prefer not to.


Second question
My program will list choices (A, B, and C) and get the user's input (x), telling what the program to do. I have it set up so that if the user input a, or A it would do the same thing, and same goes for the others. My problem is that if the user inputs W or something, I have an Else option, printing " come again ?" and asking for x again.

But if the user inputs W again, (or a few more times) the program just ends. I need some loop keeping the user at that state, or sending it back up to the beginning of the program.
This's what I got:

if (x == "a" || x == "A"){
       cout << "A list of contacts should appear" ;
       }
    else{
         cout << "Pardon me?  Please type that again... ";
         cin >> x;
}

apparently it's not working too well : /



Yet another question... How do I wrap the above code in C++ code ? I don't see the option anywhere.


I appreciate your time

Hi,
First Question:
>>>Provide more info on this
Second Question
>>>the part of code u have given is inside a while loop?
I tried something similar and it is working perfectly.

{
        string x;
        cout<<"enter a value"<<endl;
        cin>>x;
        while(1)
        {
            if(x == "a" || x== "b")
            {
                cout<<"done ..."<<endl;
                break;
            }
            else
            {
                cout<<"Re-enter a value"<<endl;
                cin>>x;
            }
        }
    }
 

Raghuram

[gpraghuram]

Hi,
First Question:
>>>Provide more info on this
Second Question
>>>the part of code u have given is inside a while loop?
I tried something similar and it is working perfectly.

{
        string x;
        cout<<"enter a value"<<endl;
        cin>>x;
        while(1)
        {
            if(x == "a" || x== "b")
            {
                cout<<"done ..."<<endl;
                break;
            }
            else
            {
                cout<<"Re-enter a value"<<endl;
                cin>>x;
            }
        }
    }
 

Raghuram

I think i answered this a litle late.......

[Hunderpanzer]

I think i answered this a litle late.......

Hehe, that's okay, I still appreciate you !

char x;
 
do
 
{
 
    cin >> x;
 
}
 
while (tolower(x) != 'a' && tolower(x) != 'b' && tolower(x) != 'c');

.

I don't understand how I can assign options with this code. I'm not sure what tolower is either...

So far, I've gotten gpraghuram's solution to work pretty nicely, though I would still like to know your way of solving this problem, python ...Can you explain it to me?

[ilikepython]

Hehe, that's okay, I still appreciate you !



.

I don't understand how I can assign options with this code. I'm not sure what tolower is either...

So far, I've gotten gpraghuram's solution to work pretty nicely, though I would still like to know your way of solving this problem, python ...Can you explain it to me?

Basically, it is just a do while loop that runs until you get the value you need. If x is not either 'a', 'b', or 'c', it asks for it again. tolower() just turns the character lowercase. That avoids having to write "x != 'A'", "x != 'B'", or "x != 'C'".

[Hunderpanzer]

Basically, it is just a do while loop that runs until you get the value you need. If x is not either 'a', 'b', or 'c', it asks for it again. tolower() just turns the character lowercase. That avoids having to write "x != 'A'", "x != 'B'", or "x != 'C'".

Ahh I see. Thanks for the help!

[Hunderpanzer]

Hello,
How would I list the strings if I wanted to be able to add contacts through the program ? Would I just have to list extra strings just in case ? I would prefer not to.

Nobody answered my question above...

I'll try figuring this out, if not, I'll see if anyone posted a tip.

Thanks

[gpraghuram]

Nobody answered my question above...

I'll try figuring this out, if not, I'll see if anyone posted a tip.

Thanks

i am not getting your question.
R u tying to maintain a list of strings?
then you can use vector<strings> and an iterator to display the strings.


Raghuram