I cannot get my numbers to square

[Brad Foster]

on my assignment I need to ask a user for two numbers

output all the odd # between the two #
output the sum of the even #
*output the # and squares between 1-10*
*output the sum of the square of the odd numbers between #1 and #2*

now I can get the first part but when it comes to the squares between 1-10 my code does not work, and I am not sure why

cout << "1 squared is: " << pow(1, 2) << endl;
cout << "2 squared is: " << pow(2, 2) << endl;
cout << "3 squared is: " << pow(3, 2) << endl;
cout << "4 squared is: " << pow(4, 2) << endl;
cout << "5 squared is: " << pow(5, 2) << endl;
cout << "6 squared is: " << pow(6, 2) << endl;
cout << "7 squared is: " << pow(7, 2) << endl;
cout << "8 squared is: " << pow(8, 2) << endl;
cout << "9 squared is: " << pow(9, 2) << endl;
cout << "10 squared is: " << pow(10, 2) << endl;

Hunderpanzer said
"Well the line of code listed above would work if the user input 1 as a number, but remember that the user can start the firstNumb at 50 and the secondNumb at 70. In your code, it would then print the squares of 1- 10 which isn't the right result."

but all I need it to do is square 1-10, but I keep getting an error.

do I need to put in more variables for the squares?

[ilikepython]

on my assignment I need to ask a user for two numbers

output all the odd # between the two #
output the sum of the even #
*output the # and squares between 1-10*
*output the sum of the square of the odd numbers between #1 and #2*

now I can get the first part but when it comes to the squares between 1-10 my code does not work, and I am not sure why

cout << "1 squared is: " << pow(1, 2) << endl;
cout << "2 squared is: " << pow(2, 2) << endl;
cout << "3 squared is: " << pow(3, 2) << endl;
cout << "4 squared is: " << pow(4, 2) << endl;
cout << "5 squared is: " << pow(5, 2) << endl;
cout << "6 squared is: " << pow(6, 2) << endl;
cout << "7 squared is: " << pow(7, 2) << endl;
cout << "8 squared is: " << pow(8, 2) << endl;
cout << "9 squared is: " << pow(9, 2) << endl;
cout << "10 squared is: " << pow(10, 2) << endl;

Hunderpanzer said
"Well the line of code listed above would work if the user input 1 as a number, but remember that the user can start the firstNumb at 50 and the secondNumb at 70. In your code, it would then print the squares of 1- 10 which isn't the right result."

but all I need it to do is square 1-10, but I keep getting an error.

do I need to put in more variables for the squares?

I don't under stand why you need all those couts when you can use a simple for loop:

for (int x = 1; x <= 10; x++)
{
    cout << x << " squared is: " << x*x << endl;
}
 

[Brad Foster]

I don't under stand why you need all those couts when you can use a simple for loop:

Code: ( cpp )
for (int x = 1; x <= 10; x++)
{
cout << x << " squared is: " << x*x << endl;
}


To be honest it is the only way I could think to do it

but I see how you are saying it just loop it so that it goes up to 10, dang that is a lot easier way to do it

how about if I needed to raise it to the third power just use
cout << x << " squared is: " << x*x*x << endl;

Thank you, I am just learning how to write programs in C++ so I don't have my head around all the great short cuts/ good ways to do things.

[sicarie]

Though the other solution is more elegant, I wanted to post in case there are any searches later with this issue. With the pow() function, you have to be sure to include the math.h library. (With that, your original code will compile and run)