log4cxx

[Bruintje Beer]

Hello,

I have a question about log4cxx. How do I make a new appender class

John

[Victor Bazarov]

Bruintje Beer wrote:

I have a question about log4cxx. How do I make a new appender class

Probably something like

appender* p = new appender;

Beyond that, ask in a forum dedicated to 'log4cxx'.

V
--
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[Jerry Coffin]

In article <f7**********@news.datemas.de>, v.********@comAcast.net
says...

Bruintje Beer wrote:

I have a question about log4cxx. How do I make a new appender class

Probably something like

appender* p = new appender;

Beyond that, ask in a forum dedicated to 'log4cxx'.

That would create a new appender object. A new appender class would be
something like:

class new_appender : public appender {
// ...
};

--
Later,
Jerry.

The universe is a figment of its own imagination.

[kwikius]

On 22 Jul, 00:48, Jerry Coffin <[e-mail]:

In article <f7oemh$[e-mail]>, [e-mail]
says...

Bruintje Beer wrote:

I have a question about log4cxx. How do I make a new appender class

Probably something like

appender* p = new appender;

Beyond that, ask in a forum dedicated to 'log4cxx'.

That would create a new appender object. A new appender class would be
something like:

class new_appender : public appender {
// ...

};

You could do with something to append and something to append to,
perhaps something like:

#include <iostream>
#include <string>

template <typename Data, typename Prev=void>
class appender{
public:
appender( Data d_in, Prev p_in): d(d_in),p(p_in){}

Data d;
Prev p;
};

template<typename Data >
class appender<Data, void>
{
public:
appender(Data d_in): d(d_in){}
Data d;
};

template<typename D, typename N>
std::ostream & operator << (std::ostream & os,appender<D,Nconst & a)
{
return os << a.p << ' ' << a.d ;
}

template<typename D>
std::ostream & operator << (std::ostream & os,appender<D,voidconst &
a)
{
os << a.d;
return os;
}

template <typename Existing,typename D>
appender<D,Existing>
append( Existing const & e,D const & d)
{
return appender<D,Existing>(d,e);
}

int main()
{
std::cout << append(

append(appender<std::string>("hello"),'&'),std::st ring("goodbye")
) <<'\n';
}

regards
Andy Little