Template traits

[Aarti]

I was trying my hand on a template class and i am getting a
compilation error

error C2146: syntax error : missing ';' before identifier
'isOptimizedImplAvailable'. Any pointers would be of great help.
Here is my code

#include <iostream>

using namespace std;

template<typename T>
class foo_traits
{
public:
static bool customImpl;
};

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

template<>
class foo_traits<char>
{
public:
static bool customImpl;
};

bool foo_traits<char>::customImpl = false;
bool foo_traits<int>::customImpl = true;

template<typename T>
class foo
{
public:
typename foo_traits<T>::customImpl isOptimizedImplAvailable()
{
return foo_traits<T>::customImpl;
}
};

int main()
{
foo<intf;
}

[Kai-Uwe Bux]

Aarti wrote:

I was trying my hand on a template class and i am getting a
compilation error

error C2146: syntax error : missing ';' before identifier
'isOptimizedImplAvailable'. Any pointers would be of great help.
Here is my code

#include <iostream>

using namespace std;

template<typename T>
class foo_traits
{
public:
static bool customImpl;
};

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

template<>
class foo_traits<char>
{
public:
static bool customImpl;
};

bool foo_traits<char>::customImpl = false;
bool foo_traits<int>::customImpl = true;

template<typename T>
class foo
{
public:
typename foo_traits<T>::customImpl isOptimizedImplAvailable()

bool isOptimizedImplAvailable()

{
return foo_traits<T>::customImpl;
}
};

int main()
{
foo<intf;
}

Best

Kai-Uwe Bux

[Aarti]

On Jul 12, 9:02 pm, Kai-Uwe Bux <[e-mail]:

Aarti wrote:

I was trying my hand on a template class and i am getting a
compilation error

error C2146: syntax error : missing ';' before identifier
'isOptimizedImplAvailable'. Any pointers would be of great help.
Here is my code

#include <iostream>

using namespace std;

template<typename T>
class foo_traits
{
public:
static bool customImpl;
};

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

template<>
class foo_traits<char>
{
public:
static bool customImpl;
};

bool foo_traits<char>::customImpl = false;
bool foo_traits<int>::customImpl = true;

template<typename T>
class foo
{
public:
typename foo_traits<T>::customImpl isOptimizedImplAvailable()

bool isOptimizedImplAvailable()

{
return foo_traits<T>::customImpl;
}
};

int main()
{
foo<intf;
}

Best

Kai-Uwe Bux- Hide quoted text -

- Show quoted text -

WOW that worked. But just for curiosity.. why did returning
foo_traits<T>::customImpl fail?

[Kai-Uwe Bux]

Aarti wrote:

On Jul 12, 9:02 pm, Kai-Uwe Bux <[e-mail]:

>Aarti wrote:

I was trying my hand on a template class and i am getting a
compilation error

error C2146: syntax error : missing ';' before identifier
'isOptimizedImplAvailable'. Any pointers would be of great help.
Here is my code

#include <iostream>

using namespace std;

template<typename T>
class foo_traits
{
public:
static bool customImpl;
};

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

template<>
class foo_traits<char>
{
public:
static bool customImpl;
};

bool foo_traits<char>::customImpl = false;
bool foo_traits<int>::customImpl = true;

template<typename T>
class foo
{
public:
typename foo_traits<T>::customImpl isOptimizedImplAvailable()

bool isOptimizedImplAvailable()

{
return foo_traits<T>::customImpl;
}
};

int main()
{
foo<intf;
}

Best

Kai-Uwe Bux- Hide quoted text -

- Show quoted text -

WOW that worked. But just for curiosity.. why did returning
foo_traits<T>::customImpl fail?

Because foo_traits<T>::customImpl is not a type but a boolean static
variable. Putting the keyword "typename" before that identifier will not
magically change its meaning.
Best

Kai-Uwe Bux
Best