c++ splitting strings but keeping the delimiter

[chezz]

Hey i looked at some earlier discussions on this topic and they seem a bit complex i found this code example on another site -

char str[]   = "200.0.0.90-200.0.0.223";
 
char *first  = strtok(str, "-");
 
char *second = strtok(NULL, "\0");
 

and i was wondering if it was possible to keep the delimiter in other words in this example the hyphen. Because in this example the hyphen is replace with a NULL and i need to keep the delimiter.
Thanks in advance, any help would be greatly appreciated.

[weaknessforcats]

Why can't you use an array of string objects??

string arr[2];
         arr[1] ="200.0.0.90";
         arr[2] ="200.0.0.223";
 

char* strings are used in C. C++ programs should use STL string objects.

[chezz]

Let me explain it a bit better, i made a decimal to binary converter and with the final output if i used a small decimal number than i will get this 00000000001010 and i wanna chop of the zeros when it reaches one but keep the one.

Also i do use string bla; , for strings rather than char bla [8]; it just i'm trying to find a viable option for doing this.

Thanks in advanced

[weaknessforcats]

Have you tried using a bitset<> and a string ??

unsigned int data = 10;
bitset<32> bits(data);     //convert data to 32 bits
string str = bits.to_string();  //convert the bits to char 1's and 0's
while (str[0] == '0')        //remove leading '0'
{
     str.erase(0,1);
}
cout << str << endl;
 

[phiefer3]

Or, you can just do this:

void chop(string& thisString)
{
    while (thisString[0] == '0')
        thisString = thisString.substr(1, thisString.length());
}

can then call it like this, if bla is your string:

chop(bla);

[phiefer3]

I thought of a method that would work faster, because it wouldn't involve a loop of function calls.

void binaryChop(string& thisString)
{
    thisString = thisString.substr(thisString.find(‘1’), thisString.length());
}

this wouldn't even need to be a function.

sorry about the double post, but I couldn't edit my other one anymore.

[chezz]

Thanks for all the advice i will try them all and see which method works best, thanks again