testing for end of line from file read

[dOleAviSc]

i have an input file with several numbers (ie 73296^4832 /n) carrot being a space and /n meaning theres another line of similar type numbers underneath. i'm trying to read them in one at a time into an array as char type and then converting them to integers, easy enough. the problem i'm having is i need my while loop to stop at the end of each line but i can't figure out how!

i tried creating a bool function within the public section of the class that i'm working on that looked like this:

bool eol(const char& k)
{
if (k == '/n')
return true;
else
return false;
}

and proceeded to implement it in my while loop as follows

ins.get(k);
while (!eol(k))
{
...
}

my compiler does not have an error that keeps it from compiling but it says

[Warning] multi-character character constant
[Warning] In function `bool eol(const char&)':
[Warning] comparison is always false due to limited range of data type

and my limited knowledge of c++ is keeping me from coming up with any alternative! does anyone know what i can do to correct this or a better way of testing for end-of-line?

[weaknessforcats]

Use the >> operator. It skips whitespace. You can use it to read your ints one after the other to the end of the file:

ifstream input("myfile.txt");
int data;
while (!input.eof())
{
     input >> data;
     cout << data << endl;
}
 

If you really need to process a line at a time, use getline:

char buffer[256]
input.geline(buffer, 256);
 

then process the buffer to get the ints. Here you might insert the buffer into a stringstream and then extract from the stringstream to your ints:

stringstream ss;
int a,b,c;
ss << buffer;
ss >> a >> b >> c;
cout << a << " " << b << " " << c << endl;
 

[dOleAviSc]

for the buffer example you used, is 256 simply an arbitrary number for your example? i've never used that method but it looks like it might do what i need. the reason i'm reading the numbers in one at a time is so that each individual integer of the numbers (not divided by spaces) is in its own array position.

so i read in the number 7345. array position 0 = 7, array position 1=3...etc.

i have to add the two entire numbers on each line (7345^4567) but one integer at a time and use the carry (add 7+5 carry 2...add 6+4(+2)...etc). thats why i was looking for an end-of-line check reading each integer in one at a time as a char.

[weaknessforcats]

There is always the option of using cin.get(). That will fetch one byte. It skips nothing. You would need to build your integers from the characters you read but you will see the \n.

All cin.getline() does is wrap a loop around cin.get().

However, if your integers a 2 per line, then you should be able to use >> operator and pull 2 integers at a time.