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What does this code do?

P: 29
can someone explain to me "what does this code do"

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  1. class baseclass
  2.    public:
  3.    virtual void runme()
  4.    {
  5.     std::cout<<"are you"<<std::endl;
  6.    }
  7. };
  8. class derivedclass :public bassclass
  9. {
  10.    public:
  11.    void runme()
  12.    {
  13.     std::cout<<"there"<<std::endl;
  14.    }
  15. }
  16. baseclass  *test_class =new Derivedclass();
  17. test_class->runme();
does the code surpose to read out.
"are you there"
Jun 14 '07 #1
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1 Reply

Expert Mod 5K+
P: 9,197
The output is: there

Your object is a derivedclass object. This object has a virtual function table (VTBL) with the addresses of all virtual functions declared in the class or inherited. The derivedclass::runme() method has overriden baseclass::runme() so it is the address of derivedclass::runme() in the VTBL.

Therefor, it is derivedclass::runme() that is called when you use the derivedclass object with a baseclass pointer or reference.

This is basic polymorphism. A program using polymorphism is an object-oriented program.
Jun 14 '07 #2

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