how can I replace a substring in a string

[silverburgh.meryl]

Hi,

If I have a string like this:
char buff[10];
buff[0] ='h';
buff[1] ='e';
buff[2] ='l';
buff[3] ='l';
buff[4] ='o';

string s(buff);

How can i replace 'll' with 'abc'
and what if I replace 'll' with 'a', will the 'o' move up by 1 index?

Thank you.

[Obnoxious User]

si***************@gmail.com skrev:

Hi,

If I have a string like this:
char buff[10];
buff[0] ='h';
buff[1] ='e';
buff[2] ='l';
buff[3] ='l';
buff[4] ='o';

buff[5] = 0;

string s(buff);

How can i replace 'll' with 'abc'
and what if I replace 'll' with 'a', will the 'o' move up by 1 index?

replace(s, "ll", "abc");

void replace(std::string &target, std::string &that, std::string &with) {
std::string::size_type where = target.find(that);
if(where != std::string::npos) {
target.replace(target.begin() + where,
target.begin() + where + that.size(),
with.begin(),
with.end());
}
}

--
OU

[Naresh Rautela]

On May 30, 10:04 am, "[e-mail]"
<[e-mail]:

Hi,

If I have a string like this:
char buff[10];
buff[0] ='h';
buff[1] ='e';
buff[2] ='l';
buff[3] ='l';
buff[4] ='o';

You need to insert a null character at postion 5.

string s(buff);

How can i replace 'll' with 'abc'

s.replace(2,2,"abc");

and what if I replace 'll' with 'a', will the 'o' move up by 1 index?

yes

>
Thank you.

[Devon Null]

si***************@gmail.com wrote:

Hi,

If I have a string like this:
char buff[10];
buff[0] ='h';
buff[1] ='e';
buff[2] ='l';
buff[3] ='l';
buff[4] ='o';

string s(buff);

How can i replace 'll' with 'abc'
and what if I replace 'll' with 'a', will the 'o' move up by 1 index?

Thank you.

Here are all the string class member functions:

http://cppreference.com/cppstring/index.html

[Roland Pibinger]

On Wed, 30 May 2007 19:30:52 +0200, Obnoxious User wrote:
[...]

>void replace(std::string &target, std::string &that, std::string &with) {

const correctness?
--
Roland Pibinger
"The best software is simple, elegant, and full of drama" - Grady Booch

[Obnoxious User]

Roland Pibinger skrev:

On Wed, 30 May 2007 19:30:52 +0200, Obnoxious User wrote:
[...]

>void replace(std::string &target, std::string &that, std::string &with) {

const correctness?

void replace(std::string & target,
std::string const & that,
std::string const & with);

--
OU

[Robbie Hatley]

<si***************@gmail.comwrote in message news:11*********************@u30g2000hsc.googlegro ups.com...

Hi,

If I have a string like this:
char buff[10];
buff[0] ='h';
buff[1] ='e';
buff[2] ='l';
buff[3] ='l';
buff[4] ='o';

Triply wrong:
1. Firstly, null-terminated strings need to be, well, null-terminated.
So you'd need to set:
buff[5] = '\0';
2. Why not just initialize the buffer to the string?
char buff[10] = "hello";
3. Why use a char[] buffer at all? Just do this:
std::string MyString ("hello");

string s(buff);

std::string

How can i replace 'll' with 'abc'

Like so (tested, working program; compile this for demo):

#include <iostream>
#include <string>
int main (void)
{
std::string S ("hello");
S.replace(S.find("ll"), 2, "abc"); // replace 2 chars at "ll" by "abc"
std::cout << S << std::endl;
return 0;
}

and what if I replace 'll' with 'a', will the 'o' move up by 1 index?

It decrements by one, from 4 to 3.

Thank you.

You're welcome.

--
Cheers,
Robbie Hatley
lone wolf aatt well dott com
triple-dubya dott Tustin Free Zone dott org

[Robbie Hatley]

"Obnoxious User" <OU@127.0.0.1wrote in message
news:46***********************@alt.teranews.com...

replace(s, "ll", "abc");

void replace(std::string &target, std::string &that, std::string &with) {
std::string::size_type where = target.find(that);
if(where != std::string::npos) {
target.replace(target.begin() + where,
target.begin() + where + that.size(),
with.begin(),
with.end());
}
}

Ewww. I could replace all of the above with just this:

s.replace(s.find("ll"), 2, "abc");

or more generically:

s.replace(s.find(target), target_size, replacement);

Far more convenient, and far less prone to error. "find" and "replace" are
already built into the std::string class, so might as well use them.

--
Cheers,
Robbie Hatley
lone wolf aatt well dott com
triple-dubya dott Tustin Free Zone dott org