What is the meaning of these lines?

[nas]

Hi..Please tell me what is the meaning of these lines

static IFastString *(*pfnlr)(const char *)=0

and

IFastString *(**ppfn)(const char *)=pfnlr

Where IFastString is the abstract class

[Gianni Mariani]

nas wrote:

Hi..Please tell me what is the meaning of these lines

static IFastString *(*pfnlr)(const char *)=0

pfnlr is a pointer to a function.

- start from the inside and read out - like this

pfnlr ->Is A

* pfnlr -pointer

(* pfnlr)(...) -to a function

(* pfnlr)(const char *) -that takes a const char * as a parameter

* (* pfnlr)(const char *) -and returns a pointer

IFastString *(*pfnlr)(const char *) -to an IFastString

static IFastString *(*pfnlr)(const char *) -it's got static storage

static IFastString *(*pfnlr)(const char *)=0 -and init to nul

e.g. The above definition is the same as:

typedef IFastString *(* T)(const char *);

static T pfnlr = 0;

In this case the "= 0" initialization is implicit for static so it's not
needed.

>
and

IFastString *(**ppfn)(const char *)=pfnlr

That would be the same as.

T * ppfn = pfnlr; // probably an error

.... should be

T * ppfn = & pfnlr;

>
Where IFastString is the abstract class

It's irrelevant what IFastString is in this discussion.

[nas]

On May 22, 3:11 am, Gianni Mariani <[e-mail]:

nas wrote:

Hi..Please tell me what is the meaning of these lines

static IFastString *(*pfnlr)(const char *)=0

pfnlr is a pointer to a function.

- start from the inside and read out - like this

pfnlr ->Is A

* pfnlr -pointer

(* pfnlr)(...) -to a function

(* pfnlr)(const char *) -that takes a const char * as a parameter

* (* pfnlr)(const char *) -and returns a pointer

IFastString *(*pfnlr)(const char *) -to an IFastString

static IFastString *(*pfnlr)(const char *) -it's got static storage

static IFastString *(*pfnlr)(const char *)=0 -and init to nul

e.g. The above definition is the same as:

typedef IFastString *(* T)(const char *);

static T pfnlr = 0;

In this case the "= 0" initialization is implicit for static so it's not
needed.

and

IFastString *(**ppfn)(const char *)=pfnlr

That would be the same as.

T * ppfn = pfnlr; // probably an error

... should be

T * ppfn = & pfnlr;

Where IFastString is the abstract class

It's irrelevant what IFastString is in this discussion.

Thank you soo much for ur reply...But now i have another question to
ask..

e.g. The above definition is the same as:

typedef IFastString *(* T)(const char *);

How is this possible?? I think syntax of the type def should be for
ex:

typedef int NINT... So whenever you write NINT, compiler replaces NINT
with int..

But in your case

typedef IFastString *(* T)(const char *);

static T pfnlr = 0;

How does complier work?

[Zeppe]

nas wrote:

On May 22, 3:11 am, Gianni Mariani <[e-mail]:

>typedef IFastString *(* T)(const char *);

How is this possible?? I think syntax of the type def should be for
ex:

typedef int NINT... So whenever you write NINT, compiler replaces NINT
with int..

you declare an int variable as

int a;

and a function pointer as

IFastString *(* a)(const char *);

as gianni explained. In the same way, you typedef an int as:

typedef int T;

and typedef a function pointer as:

IFastString *(* T)(const char *);

the syntax is specular. After the last typedef, the compiler will
replace every

T a;

with

IFastString *(* a)(const char *);

Regards,

Zeppe

[nas]

On May 22, 4:05 am, Zeppe
<zep_p@.remove.all.this.long.comment.yahoo.itwrote :

nas wrote:

On May 22, 3:11 am, Gianni Mariani <[e-mail]:

typedef IFastString *(* T)(const char *);

How is this possible?? I think syntax of the type def should be for
ex:

typedef int NINT... So whenever you write NINT, compiler replaces NINT
with int..

you declare an int variable as

int a;

and a function pointer as

IFastString *(* a)(const char *);

as gianni explained. In the same way, you typedef an int as:

typedef int T;

and typedef a function pointer as:

IFastString *(* T)(const char *);

the syntax is specular. After the last typedef, the compiler will
replace every

T a;

with

IFastString *(* a)(const char *);

Regards,

Zeppe

problem solved!!! thanks for all of u

[nas]

On May 22, 4:05 am, Zeppe
<zep_p@.remove.all.this.long.comment.yahoo.itwrote :

nas wrote:

On May 22, 3:11 am, Gianni Mariani <[e-mail]:

typedef IFastString *(* T)(const char *);

How is this possible?? I think syntax of the type def should be for
ex:

typedef int NINT... So whenever you write NINT, compiler replaces NINT
with int..

you declare an int variable as

int a;

and a function pointer as

IFastString *(* a)(const char *);

as gianni explained. In the same way, you typedef an int as:

typedef int T;

and typedef a function pointer as:

IFastString *(* T)(const char *);

the syntax is specular. After the last typedef, the compiler will
replace every

T a;

with

IFastString *(* a)(const char *);

Regards,

Zeppe

problem solved!!! thanks for all of u