Palindrome

[bluedemon]

I just wanted to know how can i remove spaces and punctuation from a user input. I've return the program for palindrome and it works for words but not for phrases with spaces and pnctuation. so far i've got the following program

#include<iostream>
#include<string>
#include<cctype>

using namespace std;

int main(void)
{

string phrase, reverse, phrase1;
short i;

cout << " Welcome to the Palindrome detection Program.\n\n";

cout << "Please enter your phrase: ";
getline(cin, phrase);

for(i = 0; i != phrase.length(); i++)

{

phrase1 = (char) tolower(phrase[i]) + phrase1;

}

for(i = 0; i != phrase.length(); i++)

{

reverse = (char) tolower(phrase[i]) + reverse;

}

cout << reverse << "\n\n";

cout << "\n\nThe phrase you entered is "
<< (phrase1 == reverse ? "a Paliindrome.\n\n"
: "not a Palindrome.\n\n");

return 0;

}

[Ganon11]

Loop through the string character by character - if a character is either a space or punctuation, remove it. You can do this by using the .substr() method to retrieve the string before the current character and the string after the current character, then concatenating the two strings back into the original string.

[bluedemon]

Loop through the string character by character - if a character is either a space or punctuation, remove it. You can do this by using the .substr() method to retrieve the string before the current character and the string after the current character, then concatenating the two strings back into the original string.

if u don't mind can u plz. give me a little example, cause i don't understand what u mean by that

[arunmib]

if u don't mind can u plz. give me a little example, cause i don't understand what u mean by that

What i would try is the following,

for(i = 0; i< phrase.length(); i++)
{
     if( (phrase[i] >97) && (phrase[i] >122) )
             cout << phrase[i];
}

The above code filters out whatever you type and just prints lowercase characters (a to z)