Variadic Functions

[baranikumarhtsl]

Hi all,
Its again me only.... no only i am learning variadic functions topic and as soon as i completed i thought to write a example function . but i got stuck up!....

See i wants to write a variadic function called xstrcpy() in which the minimum number of arguments should be 2 and max is virtually the maximum number the c compiler supports. but i don't want a parameter to specify how many arguments that i am going to pass at the time of function call...

So is there any mechanism in c/c++ to find the number of arguments that is supplied to the called function?

Here is my code for xstrcpy()

void xxstrcpy(short temp,char *dest,const char *src,...)
{
    va_list strings;
    xstrcpy(dest,src);
    va_start( strings, src) ;
    while ( temp-- )
        {
            xstrcat(dest, va_arg ( strings, char * )) ;
        }
 
    va_end ( strings ) ;
}
 
int main()
{
 
    char sstring[255];
    xxstrcpy(3,sstring,"hello ","welcome "," wih u the best"," bad programmer");
    printf("%s", sstring);
    getch();
    return 0;
}

So i wanna to get rid of the argument1 which specifies how many strings i am going to pass for the function to perform strcat() operation.



So plese help me on this!.......

[Ganon11]

I think you need that count variable to know how many arguments are passed...sorry!

[AdrianH]

So is there any mechanism in c/c++ to find the number of arguments that is supplied to the called function?

Short answer: No.

Long answer: Variadic functions have no mechanism for determining how many arguments are passed. That is why the standard requires that a variadic function has at least one non-variadic parameter.

So i wanna to get rid of the argument1 which specifies how many strings i am going to pass for the function to perform strcat() operation.

If you want to pass a bunch of strings and know how many there are, try passing them as a vector.


Adrian