If..else in loop

[flyaway888]

Hey all,

I'm writing a function that takes a number and if it is even divides it by 2 n number of times and if it is odd times it by 3 and adds one n number of times.
I use and if..else obviously to see if it is even or odd but I can only make it do the calculation once, not n times.
Should I use a for loop for it and if yes put it before the if... else or do two, one after if and one after else?

Thanks

[JosAH]

Hey all,

I'm writing a function that takes a number and if it is even divides it by 2 n number of times and if it is odd times it by 3 and adds one n number of times.
I use and if..else obviously to see if it is even or odd but I can only make it do the calculation once, not n times.
Should I use a for loop for it and if yes put it before the if... else or do two, one after if and one after else?

Thanks

I guess you want to stop the loop when the numer equals one. A while loop
would do fine here:

while (number != 1) {
   // your code here dealing with even and odd numbers
}

kind regards,

Jos

[flyaway888]

I guess you want to stop the loop when the numer equals one. A while loop
would do fine here:

while (number != 1) {
   // your code here dealing with even and odd numbers
}

kind regards,

Jos

That doesn't work because the number doesn't actually get updated so its always bigger then 1 and the compilier just keeps going.
I hope that makes sense, so the number of times it has to be done has nothing to do with the number being changed.

[JosAH]

That doesn't work because the number doesn't actually get updated so its always bigger then 1 and the compilier just keeps going.
I hope that makes sense, so the number of times it has to be done has nothing to do with the number being changed.

Then I must've misunderstood your question. From what I read you wanted to
find the series (say, starting at 10) 10, 5, 16, 8, 4, 2, 1 ...

kind regards,

Jos

[flyaway888]

Sorry, I'll try and explain it better...
Two numbers are input ( a month and a year)
the year is taken and if it is even... year = year/2
if it is odd... year = year*3+1
this happens month times
so if the month was 3 year would be updated 3 times..
Does that make any sense???

[JosAH]

Sorry, I'll try and explain it better...
Two numbers are input ( a month and a year)
the year is taken and if it is even... year = year/2
if it is odd... year = year*3+1
this happens month times
so if the month was 3 year would be updated 3 times..
Does that make any sense???

Yep, you *do* want to evaluate that series but you only want to do it 'month'
times. Have a look at this:

for (int i= 1; i <= month; i++) {
   // change the 'year' value here for even/odd values
}

kind regards,

Jos

[flyaway888]

Thanks for that, it works. I had tried it before but had a value in the wrong place.
It is amazing what one tiny little thing wrong can do!!
Thanks again

[JosAH]

Thanks for that, it works. I had tried it before but had a value in the wrong place.
It is amazing what one tiny little thing wrong can do!!
Thanks again

You're welcome of course and yes, C and C++ are extremely terse languages,
i.e. every semicolon, operator and bracket counts. There is not much syntactical
redundancy nor syntactic sugar in those languages. Actual programming is an
extremely secure activity so one better gets his/her design right first before
one has to start that tedious typing ;-)

kind regards,

Jos