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sizeof()

63
main ()
{

char i, *ppi;
i='a';
ppi=&i;
printf("%d",sizeof(ppi));

}

size of depends on address of pointer and not on the value it point too....
please tell me the actual logic...
Apr 25 '07 #1
1 905
Ganon11
3,652 Expert 2GB
It sounds like you have it. sizeof(ppi) is finding the size of a pointer. A pointer is simply a variable holding an address in memory. So sizeof() returns the size that the address takes up - on my system, the output is 4.
Apr 25 '07 #2

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