templates help

[lallous]

Hello,

I would like to define a template as:

template <class T, class R> void func(T &r)
{
r = (T)((R)r);
}

For example:
double d;
func<double, int>(d);
this would do: (double)((int)d)

1)Is this a good way to achieve this?
I don't want to use any instance of "R" but just use it to cast.

2)
How can I set that "R" is by default a "long" type?
It seems that <class T, class R = long> will only work w/ classes and not
function templates.

Regards,
Elias

[Victor Bazarov]

"lallous" <la*****@lgwm.org> wrote...

I would like to define a template as:

template <class T, class R> void func(T &r)
{
r = (T)((R)r);
}

For example:
double d;
func<double, int>(d);
this would do: (double)((int)d)

1)Is this a good way to achieve this?
I don't want to use any instance of "R" but just use it to cast.
No, type casts cannot be used as a source of information for template
type derivation. You could do

template<class R, class T> void func(T &r)
{
r = T(R(r));
}

...
double d;
...
func<int>(d); // no need to declare 'T', it will be
// derived from the argument

2)
How can I set that "R" is by default a "long" type?
It seems that <class T, class R = long> will only work w/ classes and not
function templates.

I am not sure what you mean by "will only work". Default template
arguments are allowed for functions too.

Victor