does not take number parameters

[bloomer]

This piece of code compiles fine . . .

#include <stdio.h>
#include<stdlib.h>
#include <string.h>
#include "getopt.h"
 
int main(int argc, char* argv[])
{
 
    extern char *optarg;
    extern int optind;
    char c;
 
    float number=  12.67; //default value
    float number2= 13.00;
    char name[256]="no_name";
    char optf[256]="";
    while( (c=getopt(argc, argv,"n:o:s:")) !=-1)
{
    switch (c)
    {
        case 'n':
        strncpy(optf,optarg,256);
        number=strtod(optf,NULL);
        break;
 
        case 'o':
        strncpy(optf,optarg,256);
        number2=strtod(optf,NULL);
        break;
 
        case 's':
        strncpy(name,optarg,256);
        //name=
        break;
    }
 
}
 
    printf("this is a number %e and this %e\n",number,number2);
    printf("%s\n",name);
return (0);    
 
}

but when I try to use that in a larger program (below) I get the error message getopt function does not take three parameters. But it does take three parameters. It takes three in the example above and that compiled fine. Can anyone help?

//more code here
int main (int argc, char* argv[])
 
    {
 
        extern char *optarg;
        extern int optind;
        char c;
        char optf[256]="";
        double Cu=0;
 
 
 
        while( (c=getopt(argc, argv,"a:")) !=-1)
        {
            switch (c)
            {
                case 'a':
                strncpy(optf,optarg,256);
                Cu=strtod(optf,NULL);
                printf("activity = %e",Cu);
                break;
 
            }
 
        }
//more code here
 

[sicarie]

Did you include the getopt.h in the second? Check the types, etc...?